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Minkowski-type inequalities involving Hardy function and symmetric functions
Journal of Inequalities and Applications volume 2014, Article number: 186 (2014)
Abstract
The Hardy matrix , the Hardy function and the generalized Vandermonde determinant are defined in this paper. By means of algebra and analysis theories together with proper hypotheses, we establish the following Minkowski-type inequality involving Hardy function:
As applications, our inequality is used to estimate the lower bounds of the increment of a symmetric function.
MSC:26D15, 15A15.
1 Introduction
We use the following notations throughout the paper (see [1]):
Let be an matrix over a commutative ring. Then the permanent of the matrix A, written as perA , is defined by
where is a symmetric group of n-order (see [2]). The matrix
is called a Hardy matrix, the matrix functions and are called the Hardy function (see [2, 3]) and the generalized Vandermonde determinant (see [4, 5]), respectively.
Due to the facts that the symmetric polynomial and certain symmetric functions can be expressed by the Hardy function (see [6] and Remark 1), and that the interpolating quasi-polynomial can be expressed by the generalized Vandermonde determinant (see [4, 5]), the Hardy function and the generalized Vandermonde determinant are of great significance in mathematics.
Obviously, the Hardy function is a symmetric function. For the Hardy function, we have the following well-known Hardy inequality (see[3, 7]): Let . Then the inequality
holds for any if and only if .
For the Hardy function , Wen and Wang in [2] (see Corollary 1 in [2]) obtained the following result: Let , . If
then
where
For the generalized Vandermonde determinant , Wen and Cheng in [5] (see Lemma 3 in [5]) obtained the following result: Let , . If
then we have
where
Famous Minkowski’s inequality can be described as follows (see [8, 9]): If , then for any , we have the inequality
Inequality (4) is reversed if . Equality in (4) holds if and only if x, y are linearly dependent.
Minkowski’s inequality has a wide range of applications, especially in the algebraic geometry and space science (see [8–11]). In this paper, we establish the following Minkowski-type inequality (5) involving Hardy function.
Theorem 1 (Minkowski-type inequality)
Let . If , then for any , we have the following inequality:
Equality in (5) holds if x, y are linearly dependent.
In Section 3, we demonstrate the applications of Theorem 1. Our objective is to estimate the lower bounds of the increment of a symmetric function.
2 The proof of Theorem 1
In order to prove Theorem 1, we need the following lemmas.
Lemma 1 If , , , then for any , we have the following Minkowski-type inequality:
Equality in (6) holds if x, y are linearly dependent.
Proof First of all, we consider the case
Write , . Then inequality (6) can be rewritten as
Without loss of generality, we can assume that
Indeed, if
then
where
Set
and
We arbitrarily fixed , , which satisfies condition (8), then inequality (6) can be rewritten as
We consider the following Lagrange function:
Set
and
From (11) and (12), we get
Write
Since
equation (13) can be rewritten as
By
we get
hence
By (15) and (16), we get
By (16), (17), (8) and (9), we get
According to the theory of mathematical analysis, we just need to prove that inequality (10) holds for a stationary point of and boundary points of D.
If is a stationary point of , then equality in (10) holds. Here we assume that is a boundary point of D. Then we have or . Since
inequality (10) also holds. So we have proved inequalities (7) and (6).
Next, note the continuity of both sides of (6) for the variable α, hence inequality (6) also holds if
From the above analysis we know that equality in (6) holds if , i.e., x, y are linearly dependent. This completes the proof of Lemma 1. □
Lemma 2 If and , then for any , , we have the inequality
Equation in (19) holds if and only if
Proof Write
Then inequality (19) can be rewritten as
Without loss of generality, we can assume that
and
Write
and
Then inequality (21) can be rewritten as
We define the following Lagrange function:
Set
and
Then equations (25) and (26) can be rewritten as
and
respectively. From (27) divided by (28), we get
From (29) and (27), we get
By (30) and , we get
From (31), (29), (22) and (23), we get
That is to say, the function has a unique stationary point in .
Next, we use the mathematical induction to prove that inequality (24) holds as follows.
According to the theory of mathematical analysis, we only need to prove that inequality (24) holds for a stationary point of and boundary points of . To complete our proof, we need to divide it into two steps (A) and (B).
(A) Let . If is a stationary point of in , then equality in (24) holds. Here we assume that is a boundary point of . From (23) we know that or . Hence
That is to say, inequality (24) also holds. According to the theory of mathematical analysis, inequality (24) is proved.
Let . If is a stationary point of in , then equality in (24) holds. Here we assume that is a boundary point of , then there is a 0 among , , , . Without loss of generality, we can assume that . From (23) we have
By (33), we get
That is to say, inequality (24) still holds for the case when is a boundary point of . According to the theory of mathematical analysis, we know that inequality (24) is proved.
(B) vSuppose that inequality (24) holds if we use () instead of n, we prove that inequality (24) holds as follows.
For a stationary point of in , equation in (24) holds. Here we assume that is a boundary point of , then there is a 0 among , . Without loss of generality, we can assume that . From (23), we get
Set
then equation (22) can be rewritten as
and equation (23) can be rewritten as
as well as the function can be rewritten as
By the induction hypothesis we have
By (37) and (38), we get
i.e.,
where
and
Since
we have
From and (41), we get
Combining with inequalities (39) and (42), we get
By inequality (43) we know that inequality (24) holds.
According to the theory of mathematical analysis, we know that inequality (24) is proved, hence inequality (19) is also proved by the above analysis. Inequality (19) is an equation if and only if equations (20) hold. This completes the proof of Lemma 2. □
Next we turn to the proof of Theorem 1.
Proof First of all, we prove that inequality (5) holds if and by induction for n. To complete our proof, we need to divide it into two steps (A) and (B).
-
(A)
When , then inequality (5) is an equation. Let . According to the hypothesis of Theorem 1, we know that
By Lemma 1, inequality (5) holds.
-
(B)
Suppose that inequality (5) holds if we use () instead of n, we prove that inequality (5) holds as follows.
For convenience, we use the following notations:
According to the Laplace theorem (see [2]), we obtain that
Write
By
(44), the induction hypothesis and Lemma 2, we get
That is to say, inequality (5) holds.
According to the theory of mathematical induction, inequality (5) is proved.
Next, note the continuity of both sides of (5) for the variable α. We know that inequality (5) also holds for the case
From the above analysis we know that equality in (5) holds if x, y are linearly dependent.
This completes the proof of Theorem 1. □
3 Applications in the theory of symmetric function
We use the following notations in this section (see [2, 6, 12, 13]):
If , then we call a k-degree homogeneous and symmetric polynomial (see [6]). Obviously, we have that
Theorem 1 implies the following result.
Theorem 2 Let , . Then, for any , we have the following Minkowski-type inequality:
Equality in (45) holds if x, y are linearly dependent.
Proof If , then inequality (45) is an equation. We suppose that below.
Note that
According to Theorem 1, we get
that is to say, inequality (45) is proved. Equality in (45) holds if x, y are linearly dependent by Theorem 1.
The proof of Theorem 2 is completed. □
Theorem 1 also contains the following result.
Theorem 3 Let be a symmetric function, and can be expressed as a convergent Taylor series:
where
Then, for any , we have the following inequality:
Equality in (47) holds if there is a real such that
or and x, y are linearly dependent.
Proof Obviously, we have that
Here we show that
Note the following identities:
Hence
That is to say, equation (49) holds.
Set in Theorem 1, we get
According to the A-G inequality (see [12]) or Hardy’s inequality (1), we have
Note the A-G inequality with weights:
By (48)-(52), we get
That is to say, inequality (47) holds.
According to the above analysis, we know that a sufficient condition of inequality (47) to be an equality is as follows: there is a real such that
or and x, y are linearly dependent.
This completes the proof of Theorem 3. □
Theorem 3 implies the following result.
Corollary 1 Let , . Then we have the following inequality:
Equality in (53) holds if there exists a real such that
Proof We construct an auxiliary function as follows:
i.e.,
where
Then
According to Theorem 3, for any , inequality (47) holds, i.e.,
that is to say, inequality (53) holds. Equality in (53) holds if there exists a real such that
by Theorem 3. This ends the proof. □
Corollary 1 implies the following result.
Corollary 2 Let the functions and be continuous, and let them satisfy the following conditions:
Then we have the following inequality:
Set , in Theorem 3. By
(see [6]) and Theorem 3, we have the following Corollary 3.
Corollary 3 Let , and let
Then we have the following Minkowski-type inequality:
Equality in (56) holds if x, y are linearly dependent.
Remark 1 If there exists a function such that for any , any non-negative integer k and any we have
then (46) holds and the Taylor series (46) converges (see [14]) by the theory of mathematical analysis.
Remark 2 The significance of Theorem 2 and Theorem 3 is to estimate the lower bounds of the increment of the symmetric functions
respectively.
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Acknowledgements
This work was supported in part by the Natural Science Foundation of China (No. 61309015) and in part by the Foundation of Scientific Research Project of Fujian Province Education Department of China (No. JK2012049).
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Wen, J., Wu, S. & Han, T. Minkowski-type inequalities involving Hardy function and symmetric functions. J Inequal Appl 2014, 186 (2014). https://doi.org/10.1186/1029-242X-2014-186
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DOI: https://doi.org/10.1186/1029-242X-2014-186