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On two-valued measure and double statistical convergence in 2-normed spaces

Abstract

In this paper we introduce some new double difference lacunary sequence spaces using Orlicz functions, generalized double difference sequences and a two-valued measure μ in 2-normed spaces, and we also examine some of their properties.

MSC:40H05, 40C05.

Dedication

Dedicated to Professor Hari M Srivastava

1 Introduction

The notion of summability of single sequences with respect to a two-valued measure was introduced by Connor [1, 2] as a very interesting generalization of statistical convergence which was defined by Fast [3]. Over the years, and under different names, statistical convergence was discussed in the theory of Fourier analysis, ergodic theory and number theory. Later on, it was further investigated from the sequence spaces point of view and linked with summability theory by Fridy [4], Salat [5]. The notion of statistical convergence was further extended to double sequences independently by Móricz [6] and Mursaleen et al. [7]. Savaş [8] studied statistical convergence in random 2-normed space. For more recent developments on double sequences one can consult the papers (see [916]) where more references can be found. In particular, very recently Das and Bhunia investigated the summability of double sequences of real numbers with respect to a two-valued measure and made many interesting observations [17]. In [18], Das and Savaş et al. introduced some generalized double difference sequence spaces using summability with respect to a two-valued measure and an Orlicz function in 2-normed spaces which have a unique non-linear structure. The study of Orlicz sequence spaces was initiated with a certain specific purpose in Banach space theory. Lindenstrauss and Tzafriri [19] investigated Orlicz sequence spaces in more detail and they proved that every Orlicz sequence space l M contains a subspace isomorphic to l p (1p<). The Orlicz sequence spaces are the special cases of Orlicz spaces studied in [20]. Orlicz spaces find a number of useful applications in the theory of nonlinear integral equations. Whereas the Orlicz sequence spaces are the generalization of l p -spaces, the l p -spaces find themselves enveloped in Orlicz spaces [21].

The concept of 2-normed spaces was initially introduced by Gahler [22, 23] as a very interesting non-linear extension of the idea of usual normed linear spaces. Some initial studies on this structure can be seen in [2224]. Recently a lot of interesting developments have occurred in 2-normed spaces in summability theory and related topics (see [18, 2530]).

In this paper, in a natural way, we first define statistical convergence for double sequences in 2-normed spaces using a two-valued measure and also prove some interesting theorems. Furthermore, we introduce some new sequence spaces in 2-normed spaces using Orlicz functions, generalized double difference sequences and a two-valued measure μ.

2 Preliminaries

Throughout the paper denotes the set of all natural numbers, χ A represents the characteristic function of AN and represents the set of all real numbers.

Recall that a set AN is said to have the asymptotic density d(A) if

d(A)= lim n ( 1 n ) j = 1 n χ A (j)

exists.

Definition 2.1 [3]

A sequence { x n } n N of real numbers is said to be statistically convergent to ξR if for any ϵ>0 we have d(A(ϵ))=0, where A(ϵ)={nN:| x n ξ|ϵ}.

In [31] the notion of convergence for double sequences was presented by Pringsheim.

A double sequence x={ x k l } of real numbers is said to be convergent to LR if, for any ϵ>0, there exists N ϵ N such that | x k l L|<ϵ whenever k,l N ϵ . In this case, we write lim k , l x k l =L.

A double sequence x={ x k l } of real numbers is said to be bounded if there exists a positive real number M such that | x k l |<M for all k,lN. That is, x ( , 2 ) = sup k , l N | x k l |<.

Let KN×N and let K(k,l) be the cardinality of the set {(m,n)K:mk,nl}. If the sequence { K ( k , l ) k . l } k , l N has a limit in the Pringsheim’s sense, then we say that K has double natural density and is denoted by d 2 (K)= lim k , l K ( k , l ) k . l .

A statistically convergent double sequence of elements of a metric space (X,ρ) is defined essentially in the same way (ρ( x k l ,ξ)ϵ instead of | x k l ξ|ϵ).

Throughout the paper μ will denote a complete {0,1}-valued finite additive measure defined on algebra Γ of subsets of N×N that contains all subsets of N×N that are contained in the union of a finite number of rows and columns of N×N and μ(A)=0 if A is contained in the union of a finite number of rows and columns of N×N (see [18]).

Definition 2.2 [18]

A double sequence x={ x k l } of real numbers is said to be μ-statistically convergent to LR if and only if for any ϵ>0, μ({(k,l)N×N:| x k l L|ϵ})=0.

Definition 2.3 [18]

A double sequence x={ x k l } of real numbers is said to be convergent to LR in μ-density if there exists an AΓ with μ(A)=1 such that { x k l } ( k , l ) A is convergent to L.

Definition 2.4 [23]

Let X be a real vector space of dimension d, where 2d<. A 2-norm on X is a function ,:X×XR which satisfies (i) x,y=0 if and only if x and y are linearly independent; (ii) x,y=y,x; (iii) αx,y=|α|x,y, αR; (iv) x,y+zx,y+x,z. The ordered pair (X,,) is then called a 2-normed space.

Let (X,,) be a finite dimensional 2-normed space and let u={ u 1 , u 2 ,, u d } be the basis of X. We can define the norm , on X by , =max{x, u i :i=1,,d}. Also, x y =max{xy, u j :j=1,,d}.

Let (X,,) be any 2-normed space and let S (2X) be the set of all double sequences defined over the 2-normed space (X,,). Clearly S (2X) is a linear space under addition and scalar multiplication.

Recall in [20] that an Orlicz function M:[0,)[0,) is a continuous, convex and non-decreasing function such that M(0)=0 and M(x)>0 for x>0, and M(x) as x.

Note that if M is an Orlicz function, then M(λx)λ for all λ with 0<λ<1.

In the later stage, different classes of Orlicz sequence spaces were introduced and studied by Parashar and Choudhary [32], Savaş [2830, 3338] and many others.

Definition 2.5 [18]

A double sequence x={ x k l } in a 2-normed space (X,,) is said to be convergent to L in (X,,) if for each ϵ>0 and each zX, there exists n ϵ N such that x k l L,z<ϵ for all i,j n ϵ .

Definition 2.6 [18]

Let μ be a two-valued measure on N×N. A double sequence { x k l } in a 2-normed space (X,,) is said to be μ-statistically convergent to some point x in X if for each pre-assigned ϵ>0 and for each zX, μ(A(z,ϵ))=0, where A(z,ϵ)={(k,l)N×N: x k l x,zϵ}.

Definition 2.7 Let μ be a two-valued measure on N×N. A double sequence { x k l } in a 2-normed space (X,,) is said to be μ-statistically Cauchy if for each pre-assigned ϵ>0 and for each zX, there exist integers N=N(ε,z) and M=M(ε,z) such that μ(A(z,ϵ))=0, where A(z,ϵ)={(k,l)N×N: x k l x N ( ε , z ) M ( ε , z ) ,zϵ}.

We first give the following theorem.

Theorem 2.1 Let μ be a two-valued measure on N×N and two sequences ( x k l ) and ( y k l ) in 2-normed space (X,,). If ( y k l ) is a μ-convergent sequence such that x k l = y k l a.a. (k,l), then ( x k l ) is μ-statistically convergent.

Proof Suppose μ({(k,l)N×N: x k l y k l })=0 and lim m , n y k l ,z=L,z. Then, for every ϵ>0 and zX,

{ ( k , l ) N × N : x k l L , z ε } { ( k , l ) N × N : y k l L , z ε } { ( k , l ) N × N : x k l y k l } .

Therefore

μ { ( k , l ) N × N : x k l L , z ε } μ { ( k , l ) N × N : y k l L , z ε } + μ { ( k , l ) N × N : x k l y k l } .

Since

lim m n y k l ,z=L,z

for every zX, the set

{ ( k , l ) N × N : y k l L , z ε }

contains a finite number of integers. Hence,

μ { ( k , l ) N × N : y k l L , z ε } =0.

We get

μ { ( k , l ) N × N : x k l L , z ε } =0

for every ϵ>0 and zX. Consequently, μ-st- lim k , l x k l ,z=L,z. This completes the proof. □

Theorem 2.2 Let μ be a two-valued measure on N×N and let { x k l } k , l 1 , 1 be a μ-statistically Cauchy sequence in a finite dimensional 2-normed space (X,,). Then there exits a μ-convergent sequence { y k l } k , l 1 in (X,,) such that x k l = y k l for a.a. (k,l).

Proof First suppose that { x k l } k , l 1 is a statistically Cauchy sequence in (X, , ). Choose natural numbers M 1 and N 1 such that the closed ball B u 1 , 1 = B u ( x M 1 N 1 ,1) contains x k l for a.a. (k,l). Then choose natural numbers M 2 and N 2 such that the closed ball B 2 , 2 = B u ( x M 2 N 2 , 1 ( 2.2 ) ) contains x k l for a.a. (k,l). Note that B u 2 , 2 = B u 1 , 1 B 2 , 2 also contains x k l for a.a. (k,l). Thus, by continuing this process, we can obtain a sequence { B u p , q } p , q 1 , 1 of nested closed balls such that diam{ B u p , q } 1 2 p 2 q . Therefore p , q = 1 , 1 , B u p , q ={A}. Since each B u p , q contains x k l for a.a. (k,l), we can choose a sequence of strictly increasing natural numbers { T p , q } p , q 1 such that

1 k l | { ( k , l ) N × N : x k l B u p , q } |< 1 p , q if k,l> T p , q .

Hence we have

μ { ( k , l ) N × N : x k l B u p , q } =0if k,l> T p , q .

Put W p ; q ={(k,l)N×N:(k,l)> T p , q , x k l B u p , q } for all p,q1, and W= p , q = 1 , 1 , W p , q . Now define the sequence { y k l } k l 1 as follows:

y k l = { A if  ( k , l ) W , x k l otherwise.

Note that lim k , l , y k l =A. In fact, for each ϵ>0, choose a natural number p, q such that ϵ> 1 p , q >0. Then, for each kl> T p q , or y k l =A or y k l = x k l B u p , q and so in each case y k l A diam{ B u p , q } 1 2 p 1 2 q 1 . Since {(k,l)N×N: y k l x k l }{(k,l)N×N: x k l B u p , q }, we have

μ { ( k , l ) N × N : y k l x k l } μ { ( k , l ) N × N : x k l B u p , q } .

Hence μ({(k,l)N×N: y k l x k l })=0. Thus, in the space (X, , ), y k l = x k l for a.a. (k,l). Suppose that { u 1 , u 2 ,, u d } is the basis for (X,,). Since lim m n y k l A =0 and y k l A, u i y k l A for all 1id, lim m n y k l A , z =0 for every zX. This completes the proof. □

In order to prove the equivalence of Definitions 2.5 and 2.6, we shall find it helpful to use Theorems 2.1 and 2.2.

Theorem 2.3 Let μ be a two-valued measure on N×N and let { x k l } k l 1 be a sequence in a 2-normed space (X,,). The sequence { x k l } is μ-statistically convergent if and only if { x k l } is a μ-statistically Cauchy sequence.

3 New double sequence spaces

We first state an inequality which will be used throughout this paper : If { p k l } is a bounded double sequence of non-negative real numbers and sup k , l N p k l =H and D=Max{1, 2 H 1 }, then

| a k l + b k l | p k l D { | a k l | p k l + | b k l | p k l }

for all k, l and a k l , b k l C, the set of all complex numbers. Also,

| a | p k l Max { 1 , | a | H }

for all aC.

By a lacunary sequence θ=( k r ); r=0,1,2, , where k 0 =0, we shall mean an increasing sequence of non-negative integers with k r k r 1 as r. The intervals determined by θ will be denoted by I r =( k r 1 , k r ] and h r = k r k r 1 . The ratio k r k r 1 will be denoted by q r .

Definition 3.1 The double sequence θ r , s ={( k r , l s )} is called double lacunary if there exist two increasing sequences of integers such that

k 0 =0, h r = k r k k 1 as r

and

l 0 =0, h ¯ s = l s l s 1 as s.

Let us denote k r , s = k r l s , h r , s = h r h ¯ s and θ r , s is determined by I r , s ={(k,l): k r 1 <k k r & l s 1 <l l s }, q r = k r k r 1 , q ¯ s = l s l s 1 , and q r , s = q r q ¯ s .

Definition 3.2 Suppose that as before μ is a two-valued measure on N×N and let M be an Orlicz function and (X,,) be a 2-normed space. Further, let p={ p k l } be a bounded sequence of positive real numbers. Now we introduce the following different types of sequence spaces, for all ϵ>0,

W μ ( θ 2 , M , m , p , , ) = { x S ( 2 X ) : μ ( ( k , l ) N × N : 1 h r s ( k , l ) I r s [ M ( m x k l L ρ , z ) ] p k l ϵ ) = 0 for some  ρ > 0  and  L X  and each  z X } , W 0 μ ( θ 2 , M , m , p , , ) = { x S ( 2 X ) : μ ( ( k , l ) N × N : 1 h r s ( k , l ) I r s [ M ( m x k l ρ , z ) ] p k l ϵ ) = 0 for some  ρ > 0  and each  z X } , W μ ( θ 2 , M , m , p , , ) = { x S ( 2 X ) : k > 0 , μ ( { ( k , l ) N × N : 1 h r s ( k , l ) I r s [ M ( m x k l ρ , z ) ] p k l k } ) = 0  for some  ρ > 0  and each  z X } ,

where m x k l = m 1 x k l m 1 x k + 1 , l m 1 x k , l + 1 + m 1 x k + 1 , l + 1 .

We now prove the following theorem.

Theorem 3.1 W μ (θ,M, m ,p,,), W 0 μ ( θ 2 ,M, m ,p,,) and W μ ( θ 2 ,M, m ,p,,) are linear spaces.

Proof We shall prove the theorem for W 0 μ ( θ 2 ,M, m ,p,,) and others can be proved similarly. Let ϵ>0 be given. Assume that x,y 2 W 0 μ (θ,M, m ,p,,) and α,βR, where x={ x k l } and y={ y k l }. Further let zX. Then

μ ( { ( k , l ) N × N : 1 h r s ( k , l ) I r s [ M ( m x k l ρ 1 , z ) ] p k l ϵ } ) =0
(3.1)

for some ρ 1 >0 and

μ ( { ( k , l ) N × N : 1 h r s ( k , l ) I r s [ M ( m y k l ρ 2 , z ) ] p k l ϵ } ) =0
(3.2)

for some ρ 2 >0.

Since , is 2-normed, m is linear, therefore the following inequality holds:

1 h r s ( k , l ; ) I r s [ M ( m ( α x k l + β y k l ) | α | ρ 1 + | β | ρ 2 , z ) ] p k l D 1 h r s ( k , l ) I r s [ | α | | α | ρ 1 + | β | ρ 2 M ( m x k l ρ 1 , z ) ] p st + D 1 h r s ( k , l ) I k l [ | β | | α | ρ 1 + | β | ρ 2 M ( m y k l ρ 2 , z ) ] p k l D F 1 h r s ( k , l ) I r s [ M ( m x k l ρ 1 , z ) ] p k l + D F 1 h r s ( k , l ) I r s [ M ( m y k l ρ 2 , z ) ] p k l ,

where

F=Max { 1 , [ | α | | α | ρ 1 + | β | ρ 2 ] H , [ | β | | α | ρ 1 + | β | ρ 2 ] H } .

From the above inequality we get

{ ( k , l ) N × N : 1 h r s ( k , l ) I r s [ M ( m ( α x k l + β y k l ) | α | ρ 1 + | β | ρ 2 , z ) ] p k l ϵ } { ( k , l ) N × N : D F 1 h r s ( k , l ) I r s [ M ( m x k l ρ 1 , z ) ] p k l ϵ 2 } { ( k , l ) N × N : D F 1 h r s ( k , l ) I r s [ M ( m y k l ρ 2 , z ) ] p k l ϵ 2 } .

Hence from (3.1) and (3.2) the required result is proved. □

Theorem 3.2 For any fixed (k,l)N×N, W μ ( θ 2 ,M, m ,p,,) is a paranormed space with respect to the paranorm g k l :XR, defined by

g k l ( x ) = inf z X ( k , l ) I r s x k l , z + inf { ρ p k l / H : ρ > 0  s.t.  sup ( k , l ) N × N [ M ( m x k l ρ , z ) ] p k l 1 , z X } .

Proof This can be proved by using the techniques similar to those used in Theorem 4.3 in [18]. □

Theorem 3.3 Let M, M 1 , M 2 be Orlicz functions. Then

  1. (i)

    W 0 μ ( θ 2 , M 1 , m ,p,,) W 0 μ ( θ 2 ,Mo M 1 , m ,p,,), provided { p k l } k , l N × N are such that H 0 =inf p k l >0;

  2. (ii)

    W 0 μ ( θ 2 , M 1 , m ,p,,) W 0 μ ( θ 2 , M 2 , m ,p,,) W 0 μ ( θ 2 , M 1 + M 2 , m ,p,,).

Proof (i) Let ϵ>0 be given. Choose ϵ 0 >0 such that max{ ϵ 0 H , ϵ 0 H 0 }<ϵ. Now, using the continuity of M, choose 0<δ<1 such that 0<t<δ implies that M(t)< ϵ 0 . Let { x k l } W 0 μ ( θ 2 , M 1 , m ,p,,). Now, from the definition μ(A(δ))=0, where

A(δ)= { ( k , l ) N × N : 1 h r s ( k , l ) I r s [ M 1 ( m x k l ρ , z ) ] p k l δ H } .

Thus if (k,l)A(δ), then

1 h r s ( k , l ) I r s [ M 1 ( m x k l ρ , z ) ] p k l < δ H ,

i.e.,

( r , s ) I r s [ M 1 ( m x k l ρ , z ) ] p k l < h r s δ H ,

i.e.,

[ M 1 ( m x k l ρ , z ) ] p k l < δ H

for all (k,l) I r s . Hence

[ M 1 ( m x k l ρ , z ) ] <δ

for all (k,l) I r s .

Hence, from the above, using the continuity of M, we must have

M ( [ M 1 ( m x k l ρ , z ) ] ) < ϵ 0

for all (k,l) I r s . This implies that

[ Mo M 1 ( m x k l ρ , z ) ] p k l <max { ϵ 0 H , ϵ 0 H }

for all (k,l) I r s , i.e.,

( k , l ) I r s [ Mo M 1 ( m x k l ρ , z ) ] p k l < h r s max { ϵ 0 H , ϵ 0 H } < h r s ϵ,

which again implies that

1 h r s ( r , s ) I r s [ Mo M 1 ( m x k l ρ , z ) ] p k l <ϵ.

This shows that

{ ( k , l ) N × N : 1 h r s ( k , l ) I r s [ Mo M 1 ( m x k l ρ , z ) ] p k l ϵ } A(δ).

Therefore

μ ( { ( k , l ) N × N : 1 h r s ( k , l ) I r s [ Mo M 1 ( m x k l ρ , z ) ] p k l ϵ } ) =0.

Thus

{ x k l } W 0 μ ( θ 2 , M 1 , m , p , , ) .
  1. (ii)

    Let { x k l } W 0 μ ( θ 2 , M 1 , m ,p,,) W 0 μ ( θ 2 , M 2 , m ,p,,). Then the fact that

    1 h r s [ ( M 1 + M 2 ) ( m x k l ρ , z ) ] p k l D h r s [ M 1 ( m x k l ρ , z ) ] p k l + D h r s [ M 2 ( m x k l ρ , z ) ] p k l

gives us the result. Hence this completes the proof of the theorem. □

Finally we conclude this paper by stating the following theorem.

Theorem 3.4 Let X( m 1 ), m1, stand for W μ ( θ 2 ,M, m 1 ,p,,) or W 0 μ ( θ 2 ,M, m 1 ,p,,) or W μ ( θ 2 ,M, m 1 ,p,,). Then X( m 1 )X( m ). In general, X( i )X( m ) for all i=1,2,3,,m1.

Proof We shall give the proof for W 0 μ ( θ 2 ,M, m 1 ,p,,) only. It can be proved in a similar way for W μ ( θ 2 ,M, m 1 ,p,,) and W μ 2 (θ,M, m 1 ,p,,).

Let x= { x k l } k , l N W 0 μ ( θ 2 ,M, m 1 ,p,,). Let also ϵ>0 be given. Then

μ ( { ( k , l ) N × N : 1 h r s ( k , l ) I r s [ M ( m 1 x k l ρ , z ) ] p k l ϵ } ) =0
(3.3)

for some ρ>0. Since M is non-decreasing and convex, it follows that

1 h r s ( k , l ) I r s [ M ( m x k l 4 ρ , z ) ] p k l = 1 h r s ( k , l ) I r s [ M ( m 1 x k + 1 , l + 1 m 1 x k + 1 , l m 1 x k , l + 1 + m 1 x k l 4 ρ , z ) ] p k l D 2 h r s ( k , l ) I r s ( [ 1 4 M ( m 1 x k + 1 , l + 1 ρ , z ) ] p k l + [ 1 4 M ( m 1 x k + 1 , l ρ , z ) ] p k l + [ 1 4 M ( m 1 x k , l + 1 ρ , z ) ] p k l + [ 1 4 M ( m 1 x k , l ρ , z ) ] p k l ) D 2 G h r s ( k , l ) I r s ( [ M ( m 1 x k + 1 , l + 1 ρ , z ) ] p k l + [ M ( m 1 x k + 1 , l ρ , z ) ] p k l + [ M ( m 1 x k , l + 1 ρ , z ) ] p k l + [ M ( m 1 x k , l ρ , z ) ] p k l ) ,

where G=Max{1, ( 1 4 ) H }. Hence we have

{ ( k , l ) N × N : 1 h r s ( k , l ) I r s [ M ( m x k l 4 ρ , z ) ] p k l ϵ } { ( k , l ) N × N : D 2 G h r s ( k , l ) I r s [ M ( m 1 x k + 1 , l + 1 ρ , z ) ] p k l ϵ 4 } { ( k , l ) N × N : D 2 G h r s ( k , l ) I r s [ M ( m 1 x k + 1 , l ρ , z ) ] p k l ϵ 4 } { ( k , l ) N × N : D 2 G h r s ( k , l ) I r s [ M ( m 1 x k , l + 1 ρ , z ) ] p k l ϵ 4 } { ( k , l ) N × N : D 2 G h r s ( k , l ) I r s [ M ( m 1 x k , l ρ , z ) ] p k l ϵ 4 } .

Using (3.3) we get

μ ( { ( k , l ) N × N : 1 h r s ( k , l ) I r s [ M ( m x k l 4 ρ , z ) ] p k l ϵ } ) =0.

Therefore x={ x k l } W 0 μ ( θ 2 ,M, m ,p,,). This completes the proof. □

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Savaş, E. On two-valued measure and double statistical convergence in 2-normed spaces. J Inequal Appl 2013, 347 (2013). https://doi.org/10.1186/1029-242X-2013-347

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