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Inequalities for a polynomial and its derivative
Journal of Inequalities and Applications volume 2012, Article number: 210 (2012)
Abstract
For a polynomial of degree n which has no zeros in , Liman et al. (Appl. Math. Comput. 218:949-955, 2011) established
for all with , , and . In this paper, we extend the above inequality for the polynomials having no zeros in , . Our result generalizes certain well-known polynomial inequalities.
MSC:30A10, 30C10, 30D15.
1 Introduction and statement of results
Let be a polynomial of degree n and be its derivative. Then it is well known that
and
Inequality (1.1) is a famous result due to Bernstein [1], whereas inequality (1.2) is a simple consequence of the maximum modulus principle (see [2]). Both the above inequalities are sharp, and an equality in each holds for the polynomials having all their zeros at the origin.
For the class of polynomials having no zeros in , inequalities (1.1) and (1.2) have respectively been replaced by
and
Inequality (1.3) was conjectured by Erdös and later proved by Lax [3], whereas inequality (1.4) was proved by Ankeny and Rivlin [4], for which they made use of (1.3). Both these inequalities are also sharp, and an equality in each holds for polynomials having all their zeros on .
As an extension to (1.3) and (1.4), Malik [5] and Shah [6], respectively, proved that if in , , then
and
Aziz and Dawood [7] refined inequalities (1.3) and (1.4) by proving that if is a polynomial of degree n which does not vanish in , then
and
Both these inequalities are also sharp, and an equality in each holds for with .
As a refinement of inequalities (1.7) and (1.8), Dewan and Hans [8, 9] proved that under the same assumptions, for every , and , we have
and
Both these inequalities are also sharp, and an equality in each holds for polynomials having all their zeros on .
Liman et al. [10] further generalized inequalities (1.9) and (1.10) by proving that if is a polynomial of degree n having no zeros in , then for all with , , and , we have
As an extension to inequality (1.11), we propose the following result.
Theorem 1 If is a polynomial of degree n having no zeros in , , then for all with , , and , we have
If we take in Theorem 1, then inequality (1.12) reduces to (1.11).
Theorem 1 reduces to the following result by taking .
Corollary 1.1 If is a polynomial of degree n having no zeros in , , then for every with , and , we have
Dividing both sides of inequality (1.13) by and then making , we get the following generalization of inequality (1.9).
Corollary 1.2 If is a polynomial of degree n having no zeros in , , then for every with , and , we have
Taking in Theorem 1, we also obtain the following generalization of inequality (1.10).
Corollary 1.3 If is a polynomial of degree n having no zeros in , , then for every with , and , we have
If we take in Theorem 1, then we have the following consequence.
Corollary 1.4 If is a polynomial of degree n having no zeros in , , then for every with , and , we have
If we take in Corollary 1.4, then we get
Corollary 1.5 If is a polynomial of degree n having no zeros in , , then
Taking in Corollary 1.5, inequality (1.17) reduces to inequality (1.8).
2 Lemmas
For the proof of Theorem 1, we need the following lemmas. The first lemma is due to Aziz and Zargar [11].
Lemma 2.1 If is a polynomial of degree n having all zeros in the closed disk , where , then for every and ,
Lemma 2.2 Let be a polynomial of degree n having all zeros in , where , and be a polynomial of degree not exceeding that of . If for , then for all with , , and , we have
Proof By the inequality for , any zero of that lies on , is a zero of . On the other hand, from Rouche’s theorem, it is obvious that for δ with , has as many zeros in as does. So, all the zeros of lie in . Applying Lemma 2.1, for , we get
Therefore, for any α with , we have
i.e.,
Since has all its zeros in , a direct application of Rouche’s theorem on inequality (2.3) shows that the polynomial has all its zeros in . Therefore, similar to the first paragraph, it follows that for every with and , all the zeros of the polynomial
lie in .
Replacing by , we conclude that all the zeros of
lie in for every , , and . This implies
where and .
If inequality (2.6) is not true, then there is a point with such that
Take
then , and with this choice of δ, we have for from (2.5). But this contradicts the fact that all the zeros of lie in . For β with , (2.6) follows by continuity. This completes the proof. □
If we take in Lemma 2.2, we have
Lemma 2.3 If is a polynomial of degree n having all zeros in , where , then for all with , , , we have
If we take in Lemma 2.2, we get
Lemma 2.4 Let be a polynomial of degree at most n. Then for all with , , , we have
Lemma 2.5 If is a polynomial of degree at most n, having no zeros in , where , then for all with , , and , we have
where .
Proof If we take in Lemma 2.2, the result follows. □
Lemma 2.6 Let be a polynomial of degree at most n, then for all with , , () and , we have
where .
Proof Let . For any λ with , it follows, by Rouche’s theorem, that the polynomial has no zeros in . Consequently, the polynomial
has all zeros in and for . On applying Lemma 2.2, for all with , , and , we have that
Therefore, by the equalities
or
and substituting for and , we get
As for , i.e., , by Lemma 2.4 for the polynomial , we obtain
Therefore, by a suitable choice of argument λ, we get
Rewriting the right-hand side of (2.11) by using (2.12), we can obtain
which implies
Making , we have
Then by making use of the maximum modulus principle for the polynomial when , we get
This, in conjunction with (2.13), gives the result. □
Lemma 2.7 Let be a polynomial of degree at most n having no zeros in , , then for all with , , and , we have
Proof Since does not vanish in , applying Lemma 2.5 yields
where .
Combining inequalities (2.15) and (2.10), we have
This gives the result. □
3 Proof of the theorem
The proof follows some known ideas in the literature.
Proof of Theorem 1 If has a zero on , then the result follows from Lemma 2.7. Therefore, we assume that has all zeros in . Then and for λ with , we have , where . Using Rouche’s theorem, we conclude that the polynomial has no zeros in . Consequently, the polynomial
has all its zeros in and for . Therefore, by applying Lemma 2.2 for the polynomials and , we obtain
Using the fact that
or
and substituting for and in (3.1), we get
Since the polynomial has all zeros in and , by applying Lemma 2.3 for the polynomial , one can obtain
Therefore, by a suitable choice of argument λ, we get
Combining (3.2) and (3.3), we have that
This implies
Making , one obtains
On the other hand, by Lemma 2.6, we have
Considering inequalities (3.4) and (3.5) together gives the result. □
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Acknowledgements
The author is grateful to the referees for the careful reading of the paper and for the helpful suggestions and comments. This research was supported by Shahrood University of Technology.
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Zireh, A. Inequalities for a polynomial and its derivative. J Inequal Appl 2012, 210 (2012). https://doi.org/10.1186/1029-242X-2012-210
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DOI: https://doi.org/10.1186/1029-242X-2012-210