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Lp Bounds for the parabolic singular integral operator
Journal of Inequalities and Applications volume 2012, Article number: 121 (2012)
Abstract
Let 1 < p < ∞ and n ≥ 2. The authors establish the Lp (ℝn+1) boundedness for a class of parabolic singular integral operators with rough kernels.
MR(2000) Subject Classification: 42B20; 42B25.
1 Introduction
Let α1,..., α n be fixed real numbers, α i ≥ 1. For fixed x ∈ ℝ n , the function is a decreasing function in ρ > 0. We denote the unique solution of the equation F(x, ρ) = 1 by ρ(x). Fabes and Rivière [1] showed that ρ(x) is a metric on ℝ n , and (ℝ n, ρ) is called the mixed homogeneity space related to .
For λ > 0, let . Suppose that Ω(x) is a real valued and measurable function defined on ℝ n . We say is Ω(x) is homogeneous of degree zero with respect to A λ , if for any λ > 0 and x ∈ ℝ n
Moreover, Ω(x) satisfies the following condition
where J(x') is a function defined on the unit sphere Sn-1in ℝ n , which will be defined in Section 2.
In 1966, Fabes and Rivière [1] proved that if Ω ∈ C1(Sn-1) satisfying (1.1) and (1.2), then the parabolic singular integral operator TΩ is bounded on Lp (ℝ n ) for 1 < p < ∞, where TΩ is defined by
In 1976, Nagel et al. [2] improved the above result. They showed TΩ is still bounded on Lp (ℝ n ) for 1 < p < ∞ if replacing Ω ∈ C1(Sn-1) by a weaker condition Ω ∈ L log+L(Sn-1). Recently, Chen et al. [3] improve Theorem A, the result is
Theorem A. If Ω ∈ H1(Sn-1) satisfies (1.1) and (1.2); then the operator TΩis bounded on Lp (ℝ n ) for 1 < p < ∞.
For a suitable function ϕ on [0, 1), and Γ = {(y, ϕ(ρ(y)): y ∈ ℝ n }. Define the singular integral operator Tϕ,Ωin ℝn+1along Γ by
where (x, xn+1) ∈ ℝ n × ℝ = ℝn+1.
On the other hand, we note that if α1 = ... = α n = 1, then ρ(x) = |x|, α = n and (ℝ n, ρ) = (ℝ n , |·|). In this case, Tϕ,Ωis just the classical singular integral operator along surfaces of revolution, which was studied by the authors of [4–7].
The purpose of this article is to investigate the Lp boundedness of the parabolic singular integral operator Tϕ,Ωalong Γ when Ω ∈ F β (Sn-1). For a β > 0, F β (Sn-1) denotes the set of all Ω which are integrable over Sn-1and satisfies
Condition (1.3) was introduced by Grafakos and Stefanov [8]. The examples in [8] show that there is the following relationship between F β (Sn-1) and H1(Sn-1):
We shall state our main results as follows:
Theorem 1 Let m ∈ ℕ. Suppose that ϕ is a polynomial of degree m and, whereare the all positive integers which is less than m in {α1,..., α n }. In addition, let Ω ∈ F β (Sn-1) for some β > 0 and satisfies (1.1) and (1.2), then Tϕ,Ωis bounded on Lp (ℝn+1) for.
Corollary 1 Let m ∈ ℕ. Suppose that ϕ is a polynomial and, whereare the all positive integers which is less than m in {α1,..., α n }. In addition, letand satisfies (1.1) and (1.2), then T ϕ, Ω is bounded on Lp (ℝn+1) for 1 < p < ∞.
2 Notations and lemmas
In this section, we give some notations and lemmas which will be used in the proof of Theorem 1. For any x ∈ ℝ n , set
Then dx = ρα-1J (φ1,..., φn-1)dρdσ, where , dσ is the element of area of Sn-1and ρα-1J(φ1,..., φn-1) is the Jacobian of the above transform. In [1], it was shown there exists a constant L ≥ 1 such that 1 ≤ J(φ1,..., φn-1) ≤ L and J(φ1,..., φn-1) ∈ C∞((0, 2π)n-2× (0, π)). So, it is easy to see that J is also a C∞ function in the variable y' ∈ Sn-1. For simplicity, we denote still it by J(y').
In order to prove our theorems, we need the following lemmas:
Lemma 2.1. ([9]) Let d ∈ ℕ. Suppose that γ (t): ℝ+ ↦ ℝ d satisfiesfor a fixed matrix M, and assume γ(t) doesn't lie in an affine hyperplane. Then
Lemma 2.2. ([9]) Suppose thatandare fixed real numbers, ϕ(t) is a polynomial andis a function from ℝ+to ℝn+1. For suitable f, the maximal function associated to the homogeneous curve Γ is defined by
Then for 1 < p ≤ ∞, there is a constant C > 0, independent of, the coefficient of ϕ(t) and f, such that
Lemma 2.3. Let L : ℝn+1→ ℝ n be a linear transformation. Suppose that {σ k }k∈ℤis a sequence of uniformly bounded measures on ℝ d satisfying
for ξ ∈ ℝn+1and k ∈ ℤ. For any 1 < p0< ∞ and A > 0
holds for arbitrary functions {g k }k∈ℤon ℝn+1. Then for there exists a constant C p = C(p, n) which is independent of L such that
and
for every f ∈ Lp (ℝn+1).
Proof. The main idea of the proof is taken from [7, 8], we assume that Lξ = (ξ1,..., ξ n ) = ζ for ξ = (ξ1,..., ξ n , ξn+1) ∈ ℝn+1. Choose a such that 0· ≤ ψ ≤ 1, supp(ψ) ⊆ (1/4, 4), and
For each j, we define Φ j in ℝnby
for ξ = (ξ1,..., ξn+1) ∈ ℝn+1. If we set
and let δ represent the Dirac delta on ℝ, then by (2.7), for any Schwartz function f,
where
By using (2.4) and Littlewood-Paley theory (as in [3]), one obtains that for any 1 < p0< ∞,
On the other hand, by using Plancherel's theorem and (2.3), If j > 0, using the estimate we have
Similar to the proof of (2.10), using Plancherel's theorem and (2.3), if j < 0 we get
In short
By interpolating between (2.9) and (2.12), we obtain
for
and some β > 0. Thus, (2.5) follows from (2.13). One may then use a randomization argument to derive (2.6). Lemma 2.1 is proved.
3 Proof of Theorem 1
The main idea of the proof of Theorem 1 is taken from [10]and [11]. Let Ω satisfies (1.1), (1.2), and (1.3) for some β > 0. Let Φ(y) = (y, ϕ(ρ(y))), where , m ∈ ℕ. Let D k = {y ∈ ℝ n : 2 k < ρ(y) ≤ 2k+1} and define the family of measures σ k on ℝn+1by
and σ* f(x) = supk∈ℤ(|σ k | * | f | (x).
It is easy to see that
In light of (3.2) and Lemma 2.3, it suffices to show that σ k satisfies (2.3) and (2.4).
For (ξ, ξn+1) ∈ ℝ n × ℝ, y' ∈ Sn-1, and λ ∈ ℤ. Let
Set Λ = {α i : α i is the positive integers which is less than m in {α1,..., α n } and . Then , where α i ∈ Λ, and is not a subset of {α1,..., α n }. Therefore, we get
Without loss of generality, we may assume Λ consists of r distinct numbers and let If are all distinct, by Lemma 2.1, we get immediately
If {αj} only consists of s distinct numbers, we suppose that
where s is a positive integer with 1 ≤ s ≤ n, l1, l2,..., l s are positive integers such that l1 + l2 + ··· + l s = n and are distinct. Obviously,
does not lie in an affine hyperplane in ℝs+m-r. Then using Lemma 2.1 again, there exists C > 0 such that for any vector η = (η1,..., η n ) ∈ ℝ n ,
Let , we have
On the other hand, it is easy to see that
From (3.3), (3.3') and (3.4), we get
where . Thus, by (1.3), we get
Therefore,
On the other hand, by (1.2), we can obtain
Clearly, (3.5) and (3.6) imply (2.3) holds. Finally, we shall show that (2.4) holds.
By Lemma 2.2, we obtain ||MΦ(f)|| p ≤ C||f|| p , where C > 0 is independent of k, the coefficient of ϕ(t) and f, since Ω is integrable on Sn-1, thus ||σ*(f)|| p ≤ C||f|| p . This shows (2.4) holds. This completes the proof of the Theorem 1.
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Acknowledgements
The research was supported by the NSF of China (Grant No. 10901017), NCET of China (Grant No. NCET-11-0574), and the Fundamental Research Funds for the Central Universities.
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Authors' contributions
YC carried out the parabolic singular integral operator studies and drafted the manuscript. WY participated in the study of Littlewood-Paley theory. FW conceived of the study, and participated in its design and coordination. All authors read and approved the final manuscript.
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Chen, Y., Wang, F. & Yu, W. Lp Bounds for the parabolic singular integral operator. J Inequal Appl 2012, 121 (2012). https://doi.org/10.1186/1029-242X-2012-121
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DOI: https://doi.org/10.1186/1029-242X-2012-121