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Harnack inequality for subelliptic p-Laplacian equations of Schrödinger type

Abstract

In this paper, we establish the Harnack inequality for weak solutions of nonlinear subelliptic p-Laplacian equations of Schrödinger type

k = 1 m X k ( A ( x ) X u ( x ) , X u ( x ) p 2 2 A ( x ) X k u ( x ) ) +V(x) | u ( x ) | p 2 u(x)=f(x)

when the singular potential V is in the Kato-Stummel type class with respect to the Carnot-Carathéodory metric.

MSC:35J10, 35H20.

1 Introduction

Let Ω be a bounded open subset of R N for N3. Given a family of vector fields X=( X 1 ,, X m ), we assume that each component X k =( b k 1 ,, b k N ):Ω R N is locally Lipschitz continuous for k=1,,m. We identify the vector field X k with X k u= X k ,u= j = 1 N b k j j u if u C 1 (Ω), and when u L loc 1 (Ω), it is understood in the distributional sense that

X k u= j = 1 N x j ( b k j u) ( j = 1 N x j ( b k j ) ) u

for k=1,2,,m.

In this paper, we are interested in nonlinear equations involving the subelliptic p-Laplace operator p X u= k = 1 m X k ( A ( x ) X u ( x ) , X u ( x ) p 2 2 A(x) X k u(x)) and the singular potential V belonging to the Kato-Stummel type class. We consider the nonlinear subelliptic p-Laplacian equations of Schrödinger type in Ω

k = 1 m X k ( A ( x ) X u ( x ) , X u ( x ) p 2 2 A ( x ) X k u ( x ) ) +V(x) | u ( x ) | p 2 u(x)=f(x),
(1.1)

where p>1, X k denotes the adjoint of X k and each entry of the bounded measurable coefficient matrix A(x)=( a i j (x)) satisfies a i j (x) L (Ω) and a i j (x)= a j i (x). We suppose that the operator p X satisfies the following X-ellipticity condition:

1 λ k = 1 m X k ( x ) , ξ 2 A ( x ) ξ , ξ λ k = 1 m X k ( x ) , ξ 2 ,xΩ,ξ R N ,
(1.2)

where λ is a positive constant and , denotes the standard inner product in R N . The notion of X-ellipticity was implicity introduced in [1] by Franchi and Lanconelli in 1982, after which it was intensively studied in a series of works [25], etc. In 2000, it was explicitly developed in [6] by Lanconelli and Kogoj.

For reader’s convenience, let us recall the notion of control distance (or the Carnot-Carathéodory distance) associated to the family X. An absolutely continuous path γ:[0,T]Ω R N is said to be an X-subunit if γ ˙ (t)= k = 1 m c k (t) X k (γ(t)), with k = 1 m c k 2 (t)1, for almost every t[0,T]. Assuming that Ω R N is X-connected, i.e., for every x,yΩ R N , there exists at least one X-subunit path connecting x and y, we define

d(x,y)=inf { T > 0 | γ : [ 0 , T ] Ω R N X -subunit such that  γ ( 0 ) = x , γ ( T ) = y } .

The mapping (x,y)d(x,y) is a metric on Ω R N . It can be proved that d(x,y)0 implies |xy|0, where || is the Euclidean norm. Hereafter, all the distances mentioned in this context are designated with respect to the metric d unless we indicate it specifically. In particular, B r (x) denotes the ball {y R N |d(x,y)<r} with the control metric, and |E| denotes the Lebesgue measure of the set E R N . Following the literature [2], we define the Sobolev spaces for p>1 as follows:

W 1 , p (Ω,X)= { u L p ( Ω ) | X k u L p ( Ω ) , k = 1 , 2 , , m } ,

equipped with the norm

u W 1 , p ( Ω , X ) = ( Ω ( | u | p + | X u | p ) d x ) 1 p ,

for Xu=( X 1 u,, X m u).

Before stating our main results, we present several assumptions of control distance d(,) with respect to the vector fields X in R N and the singular potential V which we will use in the next sections.

(H1) (Metric equivalence) If |xy|0d(x,y)0, then we have that |xy|0d(x,y)0.

(H2) (Homogeneous dimension) There are positive constants r 0 , C 1 , C 2 and Q>p>1 such that for all r(0, r 0 ] and xΩ, the following relation is valid:

C 1 r Q | B r ( x ) | C 2 r Q ,

where the number Q is chosen as the least integer such that the above inequality holds, which is called the homogeneous dimension of X in Ω.

From the assumptions of control distance d(,), the following Sobolev embedding inequality is valid [7]: If 1<p<Q, then W 0 1 , p ( B r ,X) L q ( B r ) for 1q Q p Q p . Furthermore, there exists a constant C=C(X,Ω)>0, then for all u W 0 1 , p ( B r ,X),

According to [8], we have the Poincaré inequality, that is, there is a positive constant C such that the following inequality holds:

where p1, . We can also refer to [7, 9] for (p,q) type for 1q p Q Q p .

For the subelliptic p-Laplace operator p X u=0 in B R , the Green function G p (x,y) is given by [5], that is, when x,y B R 4 , we have the following decay estimates:

| G p ( x , y ) | C 1 d ( x , y ) ( Q p ) / ( p 1 ) ,1<p<Q,

where B R is the smallest metric ball such that Ω 1 4 B R . Also, the Green function estimates for the divergence form of subelliptic operators with nonsmooth coefficients were obtained in [10] for p=2.

The assumption on V is that V K Q p (Ω), the Kato-Stummel type class, which means that V is a local integrable function such that lim r 0 + η p (V;r;Ω)=0, where

η p (V;r;Ω)= sup x B R { y Ω : d ( x , y ) < r } | V ( y ) | d ( x , y ) ( Q p ) / ( p 1 ) dy,1<p<Q.

Let σR, M σ , p (Ω)={V L loc 1 (Ω): V σ , p , Ω <+}, where

V σ , p , Ω = sup x Ω 0 < r < diam ( Ω ) 1 r σ { y Ω : d ( x , y ) < r } | V ( y ) | d ( x , y ) ( Q p ) / ( p 1 ) dy<+.

We remark that if σ>0 and 1<p<Q, then M σ , p (Ω) is in fact the Morrey space L 1 , μ (Ω) for some appropriate μ. Moreover, the inclusion M σ , p (Ω) K Q p (Ω) is trivial.

This article is devoted to presenting the elementary proof of the local estimate and the Harnack inequality for the solutions of Equation (1.1), which is the extension of the related results in [5, 11], where p=2 or V=0, and the Harnack inequality for p-subLaplacian in [12].

Our main results are as follows.

Theorem 1.1 Let u W loc 1 , p (Ω,X) be a weak solution to Equation (1.1), and let V,f M σ , p (Ω) with 0<σ<1 and 1<p<Q. Assume that 0<r< r 0 with B 2 r 0 Ω. Then

sup x B r | u ( x ) | C { ( 1 r Q B 2 r | u ( x ) | p d x ) 1 p + ( f σ , p , B 2 r ) 1 p 1 }

with the constant C>0 depending only on Q, p, λ and V σ , p , B 2 r 0 .

Theorem 1.2 Let u W loc 1 , p (Ω,X) be a non-negative weak solution to Equation (1.1) in Ω and B 2 r 0 Ω, and let 0<r< r 0 . Then there exists a constant C>0 depending only on Q, p, λ and V σ , p , B 2 r 0 such that

sup x B r u(x)C { inf x B r u ( x ) + ( f σ , p , B 2 r ) 1 p 1 } .

Corollary 1.1 Under the assumptions of Theorem  1.2, the non-negative weak solution u W 0 1 , p (Ω,X) of Equation (1.1) is locally Hölder continuous in Ω.

We say u W loc 1 , p (Ω) is a weak solution of Equation (1.1) if u satisfies

Ω A ( x ) X u , X u p 2 2 A ( x ) X u , X φ ( x ) dx+ Ω V(x) | u | p 2 uφ(x)dx= Ω f(x)φ(x)dx
(1.3)

for any test function φ(x) W 0 1 , p (Ω,X).

Throughout this paper, unless otherwise indicated, C is used to denote a positive constant that is not necessarily the same at each occurrence, which depends at most on Q, p, λ, V and Ω.

2 Local boundedness of solutions

The purpose of this section is to show that weak solutions of Equation (1.1) are locally bounded. To do this, we follow the technique by Serrin [13, 14].

Lemma 2.1 (Embedding lemma)

Let Ω be an open, bounded and connected set in R N , and suppose V K Q p (Ω) and 1<p<Q. Then there exists a positive constant C Q , p , λ such that for any u W 0 1 , p (Ω,X) and 0<r<diam(Ω), we have

Ω |V| | u | p dx C Q , p , λ | η p ( V ; r ; Ω ) | p 1 ( Ω | X u | p d x + 1 r p Ω | u | p d x ) .

Proof Let G p (x,y) be the Green function for p X in B r Ω. We set

ψ(x)= B r Ω V(y) G p (x,y)dy.

This is well defined, and ψ L C η p (V;r;Ω) since V K Q p (Ω). Moreover, ψ(x) is the weak solution to the equation p X ψ=V in B r Ω, and also ψ(x)=0 on ( B r Ω).

For p>1 and a,b,ε>0, it is easy to see from the Young inequality that

(2.1)
(2.2)

From the uniform X-ellipticity assumption (1.2), a direct calculation shows

1 λ | X φ | 2 A ( x ) φ , φ λ | X φ | 2 , | A ( x ) φ , ψ | λ|Xφ||Xψ|,

when φ and ψ C 1 (Ω). Assume that u W 0 1 , p ( B r Ω,X), then by the inequality (2.1), we get that

B r Ω V | u | p d x = B r Ω | u | p p X ψ d x λ p 2 p B r Ω | X ψ | p 1 | u | p 1 | X u | d x λ p 2 ε 4 B r Ω | X u | p d x + λ p 2 ( p 1 ) ( ε 4 ) 1 / ( p 1 ) B r Ω | X ψ | p | u | p d x
(2.3)

for any ε>0. In addition, we note that

B r Ω V | u | p ψ d x = B r Ω A ( x ) X ψ , X ψ p 2 2 A ( x ) X ψ , X ψ | u | p d x + p B r Ω A ( x ) X ψ , X ψ p 2 2 A ( x ) X ψ , X u ψ | u | p 1 u | u | d x .

This and the inequality (2.2) with ε=1/(2 λ p ) yield that

B r Ω | X ψ | p | u | p d x λ p 2 B r Ω A ( x ) X ψ , X ψ p 2 2 A ( x ) X ψ , X ψ | u | p d x λ p 2 B r Ω | V | | u | p ψ d x + λ p p B r Ω | X ψ | p 1 | u | p 1 | X u | | ψ | d x λ p 2 B r Ω | V | | u | p ψ d x + λ p 2 p 1 ( 2 ( p 1 ) ) p 1 B r Ω | X u | p | ψ | p d x + 1 2 B r Ω | X ψ | p | u | p d x .
(2.4)

From the inequalities (2.3) and (2.4), and the estimation of ψ, we obtain that

B r Ω V | u | p d x λ p 2 ε 4 B r Ω | X u | p d x + C Q , p , λ ( ε 4 ) 1 / ( p 1 ) η p ( V ; r ; Ω ) B r Ω | V | | u | p d x + C Q , p , λ ( ε 4 ) 1 / ( p 1 ) η p ( V ; r ; Ω ) p B r Ω | X u | p d x .
(2.5)

To complete the proof of the lemma, we employ the method of the proof of Lemma 3.3 in [15]. Given 0<δ<1, let { ψ j p } 1 l be a finite partition of unity of Ω ¯ such that supp ψ j B r j ( x j ) with x j Ω ¯ and 0< r j δ. Set Ω ={x:d(x, Ω ¯ ) ε 0 } 1 4 B R and further restrict δ< ε 0 . Therefore,

Ω V | u ψ j | p d x λ p 2 ε 4 Ω | X ( u ψ j ) | p d x + C Q , p , λ ( ε 4 ) 1 / ( p 1 ) η p ( V ; δ ; Ω ) Ω V | u ψ j | p d x + C Q , p , λ ( ε 4 ) 1 / ( p 1 ) η p ( V ; δ ; Ω ) p Ω | X ( u ψ j ) | p d x .

We now choose ε such that

C Q , p , λ η p (V;δ;Ω)= 1 2 ( ε 4 ) 1 / ( p 1 ) , C Q , p , λ η p ( V ; δ ; Ω ) p = ( ε 4 ) 1 / ( p 1 ) λ p 2 3 ε 4 ,

which implies that

Ω V | u ψ j | p d x λ p 2 ε Ω | X ( u ψ j ) | p d x λ p 2 2 p 1 ε ( Ω | X u | p | ψ j | p d x + Ω | X ψ j | p | u | p d x ) .

By summing in j, it follows that

Ω V | u | p d x λ p 2 2 p 1 ε ( Ω | X u | p | d x + j = 1 l l ( ε ) δ p Ω | u | p d x ) C Q , p , λ | η p ( V ; δ ; Ω ) | p 1 ( Ω | X u | p d x + 1 δ p Ω | u | p d x )
(2.6)

with the constant C Q , p , λ >0. It is clear that the inequality (2.6) implies the desired conclusion. □

Lemma 2.2 Let Ω be an open, bounded and connected set in R N , and suppose V M σ , p (Ω) with 0<σ<1 and 1<p<Q. Then, for any 0<ε<1, there exists a constant τ>0 such that for any u W 0 1 , p (Ω,X), we have

Ω V | u | p dxε Ω | X u | p dx+C ε τ Ω | u | p dx.

Proof Repeating the proof of Lemma 2.1 and noting η(V;δ;Ω) V σ , p δ σ , we can deduce from the inequality (2.6) that the lemma holds with τ= p ( p 1 ) σ 1 and C= C Q , p , λ , σ ( V σ , p ) p / σ as long as we choose

δ= ( ε C Q , p , λ V σ , p p 1 ) 1 ( p 1 ) σ .

 □

We are ready to show the local maximal estimates, i.e., Theorem 1.1.

Proof of Theorem 1.1 For q1 and hM<, where h is a positive number which will be determined later, we define the function F M : R + R + by

F M (t)={ t q if  0 t M , q M q 1 ( t M ) + M q if  t > M .

Note that F M (t) is non-decreasing, non-negative and bounded for each fixed M, and t F M (t)q F M (t) for any t0. Let u W loc 1 , p (Ω,X) be the weak solution to Equation (1.1), and let ν=|u|+h. We consider the function G M (u)=sign(u) 0 ν ( F M ( t ) ) p dt. It is easy to see that

G M (u)= ( F M ( ν ) ) p and | G M ( u ) | ( F M ( ν ) ) p 1 F M (ν)
(2.7)

for any <u<. Moreover, G M (u) W loc 1 , p (Ω,X).

Thus, for any non-negative function ϕ(x) C 0 (Ω), we can choose ψ(x)= ϕ p (x) G M (u(x)) as a testing function in Equation (1.1), which yields

Thus

Ω ϕ p G M ( u ) | X u | p d x λ p 2 Ω A ( x ) X u , X u p 2 2 A ( x ) X u , ϕ p G M ( u ) X u d x λ p p Ω | X u | p 1 ϕ p 1 | G M ( u ) | | X ϕ | d x + λ p 2 Ω | V | | u | p 1 ϕ p | G M ( u ) | d x + λ p 2 Ω | f ( x ) | ϕ p | G M ( u ) | d x .

Recalling that ν=|u|+h and so |Xν|=|Xu|, using the estimates (2.7) and the fact that F M (ν)q F M (ν)/ν h 1 q F M (ν), we can then obtain that

Ω | X ν | p ϕ p ( F M ( ν ) ) p d x λ p p Ω | X ν | p 1 ϕ p 1 F M ( ν ) ( F M ( ν ) ) p 1 | X ϕ | d x + λ p 2 q p 1 Ω | V ( x ) | ϕ p | F M ( ν ) | p d x + λ p 2 h 1 p q p 1 Ω | f ( x ) | ϕ p | F M ( ν ) | p d x .

Using the inequality (2.2) with ε=1/(2 λ p ), we have

Ω | X ν | p ϕ p ( F M ( ν ) ) p dx λ p 2 p 1 2 p ( p 1 ) p 1 Ω | X ϕ | p F M p dx+ λ p 2 2 q p 1 Ω W ϕ p F M p dx,

where W(x)=|V(x)|+ h 1 p |f(x)|. We set U(x)= F M (ν(x)) and assume suppϕ B 2 r , then we rewrite the inequality above as follows:

B 2 r | X U | p ϕ p dx λ p 2 p 1 2 p ( p 1 ) p 1 B 2 r | X ϕ | p U p dx+ λ p 2 2 q p 1 B 2 r W ϕ p U p dx.

Hence

B 2 r | X ( U ϕ ) | p dx λ p 2 p 1 4 p p p 1 B 2 r | X ϕ | p U p dx+ λ p 2 2 p q p 1 B 2 r W ϕ p U p dx.
(2.8)

Now we take h= ( f σ , p , B 2 r ) 1 / ( p 1 ) , and so W σ , p , B 2 r V σ , p , B 2 r +1. By Lemma 2.2 we have, for any ε>0,

B 2 r W ϕ p U p dxε B 2 r | X ( U ϕ ) | p dx+C ε τ B 2 r ϕ p U p dx

with the positive constants C and τ independent of f, u and ϕ. From this and the inequality (2.8) it follows that

B 2 r | X ( U ϕ ) | p dxC B 2 r | X ϕ | p U p dx+C q ( p 1 ) ( τ + 1 ) B 2 r ϕ p U p dx,
(2.9)

where C is a positive constant depending on Q, p and λ.

By the Sobolev embedding inequality, we get from (2.9) that

( B 2 r | U ϕ | p κ d x ) 1 / ( p κ ) C { B 2 r | X ϕ | p U p d x + q ( p 1 ) ( τ + 1 ) B 2 r ϕ p U p d x } 1 / p

with absolute constant C, where κ= Q Q p >1.

Let r 1 and r 2 be such that r r 1 < r 2 2r, taking ϕ(x) in such a way that ϕ(x)=1 in B r 1 , 0ϕ(x)1 in B r 2 and |Xϕ(x)| C r 2 r 1 , and recalling U= F M (ν) and q1, we thus obtain

( B r 1 | F M ( ν ) | p κ d x ) 1 / ( p κ ) C q 1 + τ r 2 r 1 ( B r 2 | F M ( ν ) | p d x ) 1 / p .

Letting M+, then

( B r 1 | ν | p q κ d x ) 1 / ( p q κ ) ( C q 1 + τ r 2 r 1 ) 1 / q ( B r 2 | ν | p q d x ) 1 / ( p q )
(2.10)

with the constant C independent of r 1 , r 2 , q and ν.

By the standard iteration argument [14], we set θ i =p κ i and r i =r(1+ 2 i ) for i=0,1,2, . Hence the previous inequality (2.10) becomes

ν L θ i + 1 ( B r i + 1 ) C p θ i ( 2 i + 1 r ) p θ i ( θ i p ) p θ i ( 1 + τ ) ν L θ i ( B r i ) .

Iteration yields

ν L ( B r ) ( C r ) i = 0 1 κ i i = 0 ( 2 i + 1 ) 1 κ i i = 0 ( κ i ) 1 + τ κ i ν L p ( B 2 r ) C r Q p ν L p ( B 2 r ) C ( 1 | B 2 r | B 2 r | ν | p d x ) 1 p

with the constant C independent of ν. Recalling ν=|u|+h and that h= f σ , p , B 2 r 1 / ( p 1 ) , we get the conclusion. This completes the proof of the theorem. □

3 Harnack inequality of solutions

In this section we give the proof of Theorem 1.2, i.e., the Harnack inequality.

Proof of Theorem 1.2 Proceeding as in the proof of Theorem 1.1, it is sufficient to prove the theorem by assuming r=1. The general case r1 follows by dilations. We set ν=|u|+h with h= ( f σ , p , B 3 ) 1 / ( p 1 ) and W=V+ h 1 p f, and take ψ(x)= ϕ p ν β (x) as a test function in the inequality (1.3), where ϕ(x) is a non-negative smooth function such that suppϕ(x) B 3 and βR. We obtain

λ p 2 | β | Ω | X ν | p ν β 1 ϕ p d x λ p 2 p Ω | X ν | p 1 | X ϕ | ϕ p 1 ν β d x + Ω | V ( x ) | | ν | p 1 + β ϕ p d x + Ω | f ( x ) | | ν | β ϕ p d x .

Then it follows from the Cauchy inequality that

Ω | X ν | p ν β 1 ϕ p dxC(λ) p p | β | p Ω | X ϕ | p | ν | p 1 + β dx+C(λ) p | β | Ω W ϕ p | ν | p 1 + β dx.

We set

U(x)={ ν ( x ) p 1 + β p if  β 1 p , log ν ( x ) if  β = 1 p .

Then, from the above inequality, in the case β1p, we see that

p p ( p 1 + | β | ) p Ω | X U | p ϕ p dxC(λ) p p | β | p Ω | X ϕ | p U p dx+C(λ) p | β | Ω W ϕ p U p dx,

i.e.,

Ω | X U | p ϕ p dx C 1 (λ,β) Ω | X ϕ | p U p dx+ C 2 (λ,β) Ω W ϕ p U p dx,
(3.1)

where C 1 (λ,β)= ( p 1 + | β | ) p | β | p C(λ) and C 2 (λ,β)= ( p 1 + | β | ) p | β | C(λ). Simultaneously, in the case β=1p, we can see that

Ω | X U | p ϕ p dxC(λ) 2 p Ω | X ϕ | p dx+C(λ)2 Ω W ϕ p dx.
(3.2)

To our destination, we exploit the inequality (3.2) and use Lemma 2.1 with r=3 to get

Ω | X U | p ϕ p dxC 2 p + 1 { Ω | X ϕ | p d x + Ω ϕ p d x } ,

where C is a positive constant depending only on Q, p, λ and V σ , p , B 3 . Choosing ϕ(x) in such a way that ϕ(x)=1 in B ρ ,suppϕ B 2 ρ B 3 , and |Xϕ(x)| C ρ , where B ρ is an arbitrary open ball contained in B 2 , we then obtain that

( 1 | B ρ | B ρ | X U | p d x ) 1 p C 1 ρ .

Thus, by the assumption of (H3) Poincaré inequality, we get that U is a BMO function, and so the John-Nirenberg lemma for BMO function yields that there exist positive constants q 0 and C such that

( 1 | B 2 | B 2 e q 0 U d x ) 1 q 0 ( 1 | B 2 | B 2 e q 0 U d x ) 1 q 0 C.

Set

Φ(q,r)= ( 1 | B r | B r ν q d x ) 1 q

for any real number q0 and r>0. Then from the previous inequality, recalling that U=logν, we have

Φ( q 0 ,2)CΦ( q 0 ,2).
(3.3)

Now we turn our attention to (3.1). By Lemma 2.2 we obtain

Ω | X ( U ϕ ) | p d x C C 1 ( λ , β ) Ω | X ϕ | p U p d x + C C 2 ( λ , β ) ε Ω | X ( U ϕ ) | p d x + C C 2 ( λ , β ) ε τ Ω ϕ p U p d x

with the constant C>0 depending only Q and p. We choose ε such that C C 2 (λ,β)ε=1/2, and so we deduce that

Ω | X ( U ϕ ) | p dxC C 1 (λ,β) Ω | X ϕ | p U p dx+C ( C 2 ( λ , β ) ) τ + 1 Ω ϕ p U p dx.
(3.4)

Let r 1 and r 2 be such that 0< r 1 < r 2 2, choosing ϕ(x) in such a way that ϕ(x)=1 in B r 1 , 0ϕ(x)1 in B r 2 and |Xϕ(x)| C r 2 r 1 . From (3.4) and the Sobolev embedding inequality, we obtain

( B r 1 | U | p κ d x ) 1 κ C { C 1 ( λ , β ) ( r 2 r 1 ) p + ( C 2 ( λ , β ) ) τ + 1 } B r 2 U p d x C Q , p , τ ( r 2 r 1 ) p ( 1 + p 1 | β | ) p + 1 + τ ( 1 + | β | p 1 ) ( p 1 ) ( τ + 1 ) B r 2 U p d x
(3.5)

with κ= Q Q p >1 and the constant C Q , p , τ depending only on Q, p and τ.

Put q=p1+βp1 and take the q th root of each side of (3.5) for positive q and negative q, respectively. Then by the iteration arguments used in the proof of Theorem 1.1, we choose the initial index q= q 0 with some 0< q 0 q 0 , if q>0, such that p1 lies midway between two consecutive iterates of κ i q 0 for i=1,2, , which certifies that |β| κ 1 κ + 1 (p1), and we choose the initial index q= q 0 if q<0,

sup x B 1 | ν ( x ) | CΦ ( q 0 , 2 )
(3.6)

and

inf x B 1 | ν ( x ) | CΦ( q 0 ,2).
(3.7)

Therefore, from (3.3), (3.6), (3.7) and the Hölder inequality, we have arrived at

sup x B 1 | ν ( x ) | C inf x B 1 | ν ( x ) | ,

which implies the desired conclusion of Theorem 1.2. □

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Acknowledgements

The second author is supported by the NSF of China (No. 11161044).

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Guo, Y., Jiang, Y. Harnack inequality for subelliptic p-Laplacian equations of Schrödinger type. J Inequal Appl 2013, 160 (2013). https://doi.org/10.1186/1029-242X-2013-160

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