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Interpolatory curl-free wavelets on bounded domains and characterization of Besov spaces
Journal of Inequalities and Applications volume 2012, Article number: 68 (2012)
Abstract
Based on interpolatory Hermite splines on rectangular domains, the interpolatory curl-free wavelets and its duals are first constructed. Then we use it to characterize a class of vector-valued Besov spaces. Finally, the stability of wavelets that we constructed are studied.
MR(2000) Subject Classification: 42C15; 42C40.
1 Introduction
Due to its potential use in many physical problems, like the simulation of incompressible fluids or in electromagnetism, curl-free wavelet bases have been advocated in several articles and most of the study focus on the cases of R2 and R3[1–4]. However, it is reasonable to study the corresponding wavelet bases on bounded domains because of some practical use. At the same time, the stability and the characterization of function spaces are also necessary in some applications, such as the adaptive wavelet methods. In recent years, divergence-free and curl-free wavelets on bounded domains begin to be studied [5–8]. In particular, [8] use the truncation method to obtain interpolatory spline wavelets on rectangular domains from [3]. Inspired by this, we mainly study the interpolatory 3D curl-free wavelet bases on the cube and its applications for characterizing the vector-valued Besov spaces.
In Section 2, we first give the construction of interpolatory curl-free wavelets and its duals on the cube. The characterization of a class of vector-valued Besov spaces are given in part 3. Finally, we also study the stability of the corresponding curl-free wavelets.
Now, we begin with some notations and formulae, which will be used later on. Let and stand for two cubic Hermite splines:
Similarly, the quadratic Hermite splines are defined as
Let , and . For each j ≥ j0, define the scaling functions on [0,1]:
Let , then and are two MRAs on L2([0,1]) [8]. The corresponding duals are given in the sense of distributions:
The inperpolating multi-wavelets on [0,1] as well as the wavelet spaces are defined by
with . Here and after, h j,k (·) = h(2j· -k). The corresponding duals are given by
and . Moreover, there is the following differential relations
2 Curl-free wavelets on the cube
For , the 3D curl-operator is defined as
Let I ⊆ {1, 2, 3} =: I0, define scaling functions
with
The corresponding wavelets are
Here and after, denotes the non-zero apexes of the unite cube and
Let , which is the tensor product of corresponding interpolatory scaling functions on the interval. The corresponding duals are given similarly. Furthermore, define
and the projection operators:
Lemma 2.1[8]. For smooth functions .
Proposition 2.1. For , there has .
Proof. Note that Lemma 2.1, then
which is by definition.
Proposition 2.1 is important, because it tells us that keeps curl-free property. In general, vector-valued wavelets and wavelet spaces are given, respectively, by
For and m ∈ {1, 2}3, we define
Clearly, .
To give a decomposition for , take
for i ∈ I0\{i e }. Here, we choose i e such that .
Proposition 2.2. The vector-valued function system is complete in .
Proof. It is sufficient to show the statement for j = 0. Let satisfy
for all and i ≠ i e . Here, the inner product is in L2([0,1]3). Without loss of generality, one assumes i e = 1. Then, leads to
By the definition of ψIand differential relations (1.1), one knows
Moreover, reduces to . Now, it follows that from i e = 1. Finally, and follows from the definition of .
To give the bi-orthogonal decomposition, we define
Assume I = {i, i e , i'}, then
with |ε1| = |ε2| = 1 and ε1ε2 = -1. Now, define
Here, the derivatives are meant in the sense of distributions. Now, we state the main result:
Proposition 2.3. The set is a bi-orthogonal wavelet basis of L2([0,1]3)3 with duals defined in (2.1) and (2.2).
Proof. According to Proposition 2.2, one only need show
(i) ;
(ii) ;
(iii) ;
(iv) .
The identity (i) holds obviously for i ≠ i e . For i = i e , since i ≠ ie', then i e ≠ ie', which means e ≠ e'. Finally, the result (i) follows from the bi-orthogonality of and .
Note that . Then (ii) follows from curl⋅grad = 0. Furthermore,
Then by the fact and the bi-orthogonality of , one obtains
Now, it remains to prove (iv), which is equivalent to
It is easily proved, when e1 = e2: In fact, since , one can assume i1 = i2 and , because leads to (2.3) obviously. In that case, the left-hand side of (2.3) reduces to , which is the desired. To the end, it is sufficient to prove that for e1 ≠ e2, that is
Note that . Then the conclusion is obvious when . When , then and the left-hand side of (2.4) reduces to . Hence one only need to show (2.4), when . However, (2.4) becomes
in that case. Since , two cases should be considered: and . Using , the left-hand side of (2.5) is
in the first case; In the second one, the left-hand side of (2.5) becomes . According to the differential relation (1.1), is a linear combination of . By the bi-orthogonality of and , one receives the desired conclusion.
3 Characterization for Besov spaces
We shall characterize a class of vector-valued Besov spaces in this section. For 0 < p, q ≤ ∞ and s > 0, the Besov space is the set of all f ∈ Lp(Ω) such that
with m = [s] + 1 and ω m (f, 2-j, Lp(Ω)) the classical m-order modulus of smoothness. The corresponding norm is defined by
Our Besov space is defined as
with the norm
Clearly, , when .
The following lemma is easily proved by the definition of modulus of smoothness:
Lemma 3.1. If , then .
For and α j = (α j,k ) k , define
Lemma 3.2[8]. If is compactly supported, 0 < p, q ≤ ∞ and 0 < s < σ, then
where ∇ j =: {k : suppϕ(2j⋅ -k) ⊆ [0,1] n}.
Theorem 3.1. Let , and be defined in Section 2. If 0 and 0 < p, q ≤ ∞, then one has
Proof. It is enough to prove the following inequality:
-
(i)
;
-
(ii)
;
-
(iii)
.
Let and h ν be the ν th component of . Then, for μ ≠ i,
Since and , then both and are in the Besov space , due to Lemma 3.1. Moreover, Lemma 3.2 implies and . Note that h ν = 0 for ν ≠ i. Finally, the first inequality follows from the definition.
Let and g ν be the ν th component of . Then
Similar to the above, . According to Lemma 3.2,
Finally, one receives the second inequality and the last one follows analogously.
Let denotes the Sobolev space with regularity exponent μ and domain D. Moreover,
Furthermore, let σ j,k = 2-j([0,1]3 + k) for , the boundary cases are: when there is only one k i = 2j(1 ≤ i ≤ 3), σ j,k is defined as replacing the i th position of 2-j([k1, k1 + 1] ⊗ [k2, k2 +1] ⊗ [k3, k3 +1]) by [2j-1, 2j]; when k i = ki'= 2ifor i, i' ∈ {1, 2, 3}, both the positions i and i' are replaced by [2j-1, 2j]; finally, .
Lemma 3.3[8]. Let .
Then
The following lemma can be easily proved, but it is important for proving Theorem 3.2:
Lemma 3.4. The following relations hold:
Theorem 3.2. Let and 0 < p, q ≤ ∞. Then satisfy
Proof. One only need to show the following inequality:
-
(i)
;
-
(ii)
;
-
(iii)
.
Note that . Then one assumes i = 1 without loss of generality and proves first
By the embedding property, for , and
When for m1 = 1 or for m1 = 2.
Using (3.1), one obtains
When m3 = 2 (similarly for m2 = 2), we obtain
Note that , then the same arguments as above lead to (i).
For , we first claim that there are only the following two cases:
-
(a)
or ;
-
(b)
or .
In fact, by the vanishing moment property of the dual wavelets, that is,
Then for each P ∈ Π2. Hence, if ei'= 1 or ei'= 0 but mi'= 2, the differential relation (1.1) implies that
Moreover, the (a) part follows from the definition of ; If ei'= 0 and mi'= 1,
and the (b) part follows.
Now, one is ready to estimate and . By the definition of , one knows
Define and . Then, it is sufficient to show
Let in our claim. Then or . By and Lemma 3.3, one receives that
Similarly, holds and .
Finally, to estimate , one assumes without loss of generality that i e = 1 and . Note that and . Then with i, l ∈ {2, 3} and i ≠ l, when e2 = 1 or e3 = 1 or m2 = 2 or m3 = 2. Similar to the last case, one obtains
and (iii) is proved in these cases. Now it remains to show (iii), when e2 = e3 = 0 and m2 = m3 = 1:
For each P ∈ Π2, let g(x1,·, x3) be a primitive of P(x1,·,x3), i.e.
moreover, if k2 = 1,2,...,2jand if k2 = 0. Since e1 = 1 and has vanishing moments of order 2, then we obtain
Therefore, we have
The desired result follows from Lemma 3.3.
It should be pointed out that there is no common range for s in Theorems 3.1 and 3.2. Indeed, this is a big shortcoming. However, we need only one estimate in many cases.
4 The stability of curl-free wavelet bases
In this part, we shall prove that the single-scale wavelet bases that we have constructed in Section 2 are stable. The following lemma is the classical result of functional analysis:
Lemma 4.1. Let X be a Banach space and x1, x2,...,x n ⊆ X be linearly independent. Then there exists a constant C > 0 such that for any scalars α1, α2,..., α n , one has
Lemma 4.2[8]. Let X be a Banach space and fi 1, fi 2,..., in i ⊆ X be linearly independent for each i = 1, 2,..., m, then the tensor products are also linearly independent.
Theorem 4.1. The function system generates a Riesz basis for with Riesz bounds independent of j.
Proof. By Proposition 2.2, one need only show the stability of the function system. Let
Then for s > 0. Since , then . Moreover, one receives
due to Theorem 3.1. Now, it remains to prove the lower bound. Let , then . We take an example for e = (0, 0, 1) and m = (2,1,1),
For each fixed , by the characteristics of supports, Lemma 4.1 and 4.2, one has
Finally, the lower estimation follows from
Corollary 4.2. The system is a Riesz basis for with bounds independent of j.
Proof. Note that and curl·grad = 0. Then the desired result follows from the fact that is curl-free if and only if for all .
References
Deriaz E, Perrier V: Towards a divergence-free wavelet method for the simulation of 2D/3D turbulent flows. J Turbul 2006, 7(3):37.
Deriaz E, Perrier V: Orthogonal Helmholtz decomposition in arbitrary dimension using divergence-free and curl-free wavelets. Appl Comput Harmon Anal 2009, 26(2):249–269. 10.1016/j.acha.2008.06.001
Bittner K, Urban K: On interpolatory divergence-free wavelets. Math Comput 2007, 76: 903–929. 10.1090/S0025-5718-06-01949-1
Urban K: Wavelet bases in H (div) and H (curl). Math Comput 2001, 70(234):739–766.
Stevenson R: Divergence-free wavelet bases on the hypercube. Appl Comput Harmon Anal 2011, 30: 1–19. 10.1016/j.acha.2010.01.007
Stevenson R: Divergence-free wavelet bases on the hypercube: Free-slip boundary conditions, and applications for solving the instationary Stokes equations. Math Comput 2011, 80: 1499–1523. 10.1090/S0025-5718-2011-02471-3
Harouna SK, Perrier V: Divergence-free and curl-free wavelets on the square for numerical simulations. Math Models Methods Appl Sci, Preprint [http://hal.inria.fr/hal-00558474/PDF/perrier-kadri.pdf]
Zhao J: Interpolatory Hermite splines on rectangular domains. Appl Math Comput 2010, 216: 2799–2813. 10.1016/j.amc.2010.03.130
Acknowledgements
This is supported by the 863 Project of China(No. 2012AA011005), the project of Guangxi Innovative Team(No. 2012jjGAG0001), the National Natural Science Foundation of China (No.11161014, 11001062) and the fund of Education Department of Guangxi (No.201012M9094, 201102ZD015, 201106LX172).
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Jiang, Y. Interpolatory curl-free wavelets on bounded domains and characterization of Besov spaces. J Inequal Appl 2012, 68 (2012). https://doi.org/10.1186/1029-242X-2012-68
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DOI: https://doi.org/10.1186/1029-242X-2012-68