- Research Article
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Convergence Theorems Concerning Hybrid Methods for Strict Pseudocontractions and Systems of Equilibrium Problems
Journal of Inequalities and Applications volume 2010, Article number: 396080 (2010)
Abstract
Let be
strict pseudo-contractions defined on a closed and convex subset
of a real Hilbert space
. We consider the problem of finding a common element of fixed point set of these mappings and the solution set of a system of equilibrium problems by parallel and cyclic algorithms. In this paper, new iterative schemes are proposed for solving this problem. Furthermore, we prove that these schemes converge strongly by hybrid methods. The results presented in this paper improve and extend some well-known results in the literature.
1. Introduction
Let be a real Hilbert space with inner product
and norm
. Let
be a nonempty, closed, and convex subset of
.
Let be a countable family of bifunctions from
to
, where
is the set of real numbers. Combettes and Hirstoaga [1] considered the following system of equilibrium problems:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ1_HTML.gif)
where is an arbitrary index set. If
is a singleton, then problem (1.1) becomes the following equilibrium problem:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ2_HTML.gif)
The solution set of (1.2) is denoted by .
A mapping of
is said to be a
-strict pseudocontraction if there exists a constant
such that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ3_HTML.gif)
for all ; see [2]. We denote the fixed point set of
by
, that is,
.
Note that the class of strict pseudocontractions properly includes the class of nonexpansive mappings which are mapping on
such that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ4_HTML.gif)
for all . That is,
is nonexpansive if and only if
is a 0-strict pseudocontraction.
The problem (1.1) is very general in the sense that it includes, as special cases, optimization problems, variational inequalities, minimax problems, Nash equilibrium problem in noncooperative games, and others; see, for instance, [1, 3, 4] and the references therein. Some methods have been proposed to solve the equilibrium problem (1.1); related work can also be found in [5–8].
Recently, Acedo and Xu [9] considered the problem of finding a common fixed point of a finite family of strict pseudo-contractive mappings by the parallel and cyclic algorithms. Very recently, Duan and Zhao [10] considered new hybrid methods for equilibrium problems and strict pseudocontractions. In this paper, motivated by [5, 8–12], applying parallel and cyclic algorithms, we obtain strong convergence theorems for finding a common element of the fixed point set of a finite family of strict pseudocontractions and the solution set of the system of equilibrium problems (1.1) by the hybrid methods.
We will use the following notations:
(1) for the weak convergence and
for the strong convergence,
(2) denotes the weak
-limit set of
.
2. Preliminaries
We will use the facts and tools in a real Hilbert space which are listed below.
Lemma 2.1.
Let be a real Hilbert space. Then the following identities hold:
(i)
(ii)
Lemma 2.2 (see [6]).
Let be a real Hilbert space. Given a nonempty, closed, and convex subset
, points
, and a real number
, then the set
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ5_HTML.gif)
is convex (and closed).
Recall that given a nonempty, closed, and convex subset of a real Hilbert space
, for any
, there exists the unique nearest point in
, denoted by
, such that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ6_HTML.gif)
for all . Such a
is called the metric (or the nearest point) projection of
onto
. As we all know
if and only if there holds the relation
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ7_HTML.gif)
Lemma 2.3 (see [13]).
Let be a nonempty, closed, and convex subset of
. Let
be a sequence in
and
. Let
. Suppose that
is such that
and satisfies the following condition:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ8_HTML.gif)
Then .
Proposition 2.4 (see [9]).
Let be a nonempty, closed, and convex subset of a real Hilbert space
.
(i)If is a
-strict pseudocontraction, then
satisfies the Lipschitz condition
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ9_HTML.gif)
(ii)If is a
-strict pseudocontraction, then the mapping
is demiclosed (at 0). That is, if
is a sequence in
such that
and
, then
.
(iii)If is a
-strict pseudocontraction, then the fixed point set
of
is closed and convex. Therefore the projection
is well defined.
(iv)Given an integer , assume that, for each
,
is a
-strict pseudocontraction for some
. Assume that
is a positive sequence such that
. Then
is a
-strict pseudocontraction, with
(v)Let and
be given as in item (iv). Suppose that
has a common fixed point. Then
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ10_HTML.gif)
Lemma 2.5 (see [2]).
Let be a
-strict pseudocontraction. Define
by
for any
. Then, for any
,
is a nonexpansive mapping with
.
For solving the equilibrium problem, let one assume that the bifunction satisfies the following conditions:
(A1) for all
(A2) is monotone, that is,
for any
(A3)for each
(A4) is convex and lower semicontinuous for each
Lemma 2.6 (see [3]).
Let be a nonempty, closed, and convex subset of
, let
be bifunction from
to
which satisfies conditions (A1)–(A4), and let
and
. Then there exists
such that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ11_HTML.gif)
Lemma 2.7 (see [1]).
For , define the mapping
as follows:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ12_HTML.gif)
for all . Then, the following statements hold:
(i) is single valued;
(ii) is firmly nonexpansive, that is, for any
,
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ13_HTML.gif)
(iii);
(iv) is closed and convex.
3. Parallel Algorithm
In this section, we apply the hybrid methods to the parallel algorithm for finding a common element of the fixed point set of strict pseudocontractions and the solution set of the problem (1.1) in Hilbert spaces.
Theorem 3.1.
Let be a nonempty, closed, and convex subset of a real Hilbert space
, and let
be bifunctions from
to
which satisfies conditions (A1)–(A4). Let, for each
,
be a
-strict pseudocontraction for some
. Let
Assume that
. Assume also that
is a finite sequence of positive numbers such that
for all
and
for all
. Let the mapping
be defined by
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ14_HTML.gif)
Given , let
,
and
, be sequences which are generated by the following algorithm:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ15_HTML.gif)
where for some
,
for some
, and
satisfies
for all
. Then,
converge strongly to
.
Proof.
Denote for every
and
for all
. Therefore
. The proof is divided into six steps.
Step 1.
The sequence is well defined.
It is obvious that is closed and
is closed and convex for every
. From Lemma 2.2, we also get that
is convex.
Take , since for each
,
is nonexpansive,
, and
, we have
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ16_HTML.gif)
for all . From Proposition 2.4, Lemma 2.5, and (3.3), we get
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ17_HTML.gif)
So for all
. Thus
Next we will show by induction that
for all
. For
, we have
. Assume that
for some
. Since
, we obtain
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ18_HTML.gif)
As by induction assumption, the inequality holds, in particular, for all
. This together with the definition of
implies that
. Hence
holds for all
Thus
, and therefore the sequence
is well defined.
Step 2.
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ19_HTML.gif)
From the definition of we imply that
. This together with the fact that
further implies that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ20_HTML.gif)
Then is bounded and (3.6) holds. From (3.3), (3.4), and Proposition 2.4 (i), we also obtain that
,
,and
are bounded.
Step 3.
The following limit holds:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ21_HTML.gif)
From and
, we get
. This together with Lemma 2.1 (i) implies that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ22_HTML.gif)
Then , that is, the sequence
is nondecreasing. Since
is bounded,
exists. Then (3.8) holds.
Step 4.
The following limit holds:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ23_HTML.gif)
From , we have
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ24_HTML.gif)
By (3.6), we obtain
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ25_HTML.gif)
Next we will show that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ26_HTML.gif)
Indeed, for , it follows from the firm nonexpansivity of
that for each
we have
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ27_HTML.gif)
Thus we get
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ28_HTML.gif)
which implies that, for each
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ29_HTML.gif)
Therefore, by the convexity of and Lemma 2.5, we get
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ30_HTML.gif)
It follows that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ31_HTML.gif)
Since , we get from (3.12) that (3.13) holds; then we have
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ32_HTML.gif)
Observe that we also have
as
. On the other hand, from
, we observe that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ33_HTML.gif)
From , (3.19), and
, we obtain
as
. It is easy to see that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ34_HTML.gif)
Combining the above arguments and (3.2), we have
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ35_HTML.gif)
Now, it follows from that
as
.
Step 5.
The following implication holds:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ36_HTML.gif)
We first show that . To this end, we take
and assume that
as
for some subsequence
of
.Without loss of generality, we may assume that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ37_HTML.gif)
It is easily seen that each and
. We also have
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ38_HTML.gif)
where Note that, by Proposition 2.4,
is a
-strict pseudocontraction and
. Since
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ39_HTML.gif)
we obtain by virtue of (3.10) and (3.24) that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ40_HTML.gif)
So by the demiclosedness principle (Proposition 2.4 (ii)), it follows that , and hence
.
Next we will show that . Indeed, by Lemma 2.6, we have that, for each
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ41_HTML.gif)
From (A2), we get
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ42_HTML.gif)
Hence,
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ43_HTML.gif)
From (3.13), we obtain that as
for each
(especially,
). Together with (3.13) and (A4) we have, for each
that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ44_HTML.gif)
For any and
, let
. Since
and
, we obtain that
, and hence
. So, we have
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ45_HTML.gif)
Dividing by t, we get, for each that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ46_HTML.gif)
Letting and from (A3), we get
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ47_HTML.gif)
for all and
for each
that is,
Hence (3.23) holds.
Step 6.
From (3.6) and Lemma 2.3, we conclude that , where
.
Remark 3.2.
In 2007, Acedo and Xu studied the following CQ method [9]:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ48_HTML.gif)
In this paper, we first turn the strict pseudocontraction into nonexpansive mapping
then replace
with a more simple form in the iterative algorithm.
Remark 3.3.
If ,
, and
, we can obtain [14, Theorem
].
Remark 3.4.
If ,
,
, and
and we use
to replace
, we can get the result that has been studied by Tada and Takahashi in [8] for nonexpansive mappings. If
,
,
, and
, we can get [7, Theorem
].
Theorem 3.5.
Let be a nonempty, closed, and convex subset of a real Hilbert space
, and let
be bifunctions from
to
which satisfies conditions (A1)–(A4). Let, for each
,
be a
-strict pseudocontraction for some
. Let
Assume that
. Assume also that
is a finite sequence of positive numbers such that
for all
and
for all
. Let the mapping
be defined by
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ49_HTML.gif)
Given , let {
}, {
}, and {
} be sequences which are generated by the following algorithm:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ50_HTML.gif)
where for some
,
for some
, and,
satisfies
for all
. Then,
converge strongly to
.
Proof.
The proof of this theorem is similar to that of Theorem 3.1.
Step 1.
The sequence is well defined. We will show by induction that
is closed and convex for all
. For
, we have
which is closed and convex. Assume that
for some
is closed and convex; from Lemma 2.2, we have that
is also closed and convex; The proof of
is similar to the one in Step 1 of Theorem 3.1.
Step 2.
for all
, where
Step 3.
as
Step 4.
as
Step 5.
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_IEq322_HTML.gif)
Step 6.
.
The proof of Step 2–Step 6 is similar to that of Theorem 3.1.
Remark 3.6.
If , we can obtain the two corresponding theorems in [10].
4. Cyclic Algorithm
Let be a closed, and convex subset of a Hilbert space
, and let
be
-strict pseudocontractions on
such that the common fixed point set
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ51_HTML.gif)
Let and let
be a sequence in
. The cyclic algorithm generates a sequence
in the following way:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ52_HTML.gif)
In general, is defined by
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ53_HTML.gif)
where , with
.
Theorem 4.1.
Let be a nonempty, closed, and convex subset of a real Hilbert space
and let
be bifunctions from
to
which satisfies conditions (A1)–(A4). Let, for each
,
be a
-strict pseudocontraction for some
. Let
Assume that
. Given
, let {
}, {
}, and {
} be sequences which are generated by the following algorithm:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ54_HTML.gif)
where for some
,
for some
, and
satisfies
for all
. Then,
converge strongly to
.
Proof.
The proof of this theorem is similar to that of Theorem 3.1. The main points are the following.
Step 1.
The sequence is well defined.
Step 2.
for all
, where
Step 3.
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_IEq366_HTML.gif)
Step 4.
To prove the above steps, one simply replaces
with
in the proof of Theorem 3.1.
Step 5.
Indeed, let
and
for some subsequence
of
. We may assume that
for all
. Since, by
, we also have
for all
, we deduce that
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ55_HTML.gif)
Then the demiclosedness principle implies that for all
. This ensures that
.The Proof of
is similar to that of Theorem 3.1.
Step 6.
The sequence converges strongly to
The strong convergence to of
is a consequence of Step 2, Step 5, and Lemma 2.3.
Theorem 4.2.
Let be a nonempty, closed, and convex subset of a real Hilbert space
, and let
be bifunctions from
to
which satisfies conditions (A1)–(A4). Let, for each
,
be a
-strict pseudocontraction for some
. Let
Assume that
. Given
, let {
}, {
}, and {
} be sequences whic are generated by the following algorithm:
![](http://media.springernature.com/full/springer-static/image/art%3A10.1155%2F2010%2F396080/MediaObjects/13660_2010_Article_2142_Equ56_HTML.gif)
where for some
,
for some
, and
satisfies
for all
. Then,
converge strongly to
.
Proof.
The proof of this theorem is similar to that of Step 1 in Theorem 3.5 and Step 2–Step 6 in Theorem 4.1.
Remark 4.3.
If , we can obtain the two corresponding theorems in [10].
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Acknowledgment
This research is supported by Fundamental Research Funds for the Central Universities (GRANT:ZXH2009D021).
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Duan, P. Convergence Theorems Concerning Hybrid Methods for Strict Pseudocontractions and Systems of Equilibrium Problems. J Inequal Appl 2010, 396080 (2010). https://doi.org/10.1155/2010/396080
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DOI: https://doi.org/10.1155/2010/396080