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Subnormal Solutions of Second-Order Nonhomogeneous Linear Differential Equations with Periodic Coefficients
Journal of Inequalities and Applications volume 2009, Article number: 416273 (2009)
Abstract
We obtain the representations of the subnormal solutions of nonhomogeneous linear differential equation , where
and
are polynomials in
such that
and
are not all constants,
. We partly resolve the question raised by G. G. Gundersen and E. M. Steinbart in 1994.
1. Introduction
We use the standard notations from Nevanlinna theory in this paper (see [1–3]).
The study of the properties of the solutions of a linear differential equation with periodic coefficients is one of the difficult aspects in the complex oscillation theory of differential equations. However, it is also one of the important aspects since it relates to many special functions. Some important researches were done by different authors; see, for instance, [4–9].
Now, we firstly consider the second-order homogeneous linear differential equations

where and
are polynomials in
and are not both constants. It is well known that every solution
of (1.1) is an entire function.
Let be an entire function. We define

to be the -type order of
.
If is a solution of (1.1) and if
satisfies
, then we say that
is a subnormal solution of (1.1). For convenience, we also say that
is a subnormal solution of (1.1).
-
H.
Wittich has given the general forms of all subnormal solutions of (1.1) that are shown in the following theorem.
Theorem 1 A (see [9]).
If is a subnormal solution of (1.1), where
and
are polynomials in
and are not both constants, then
must have the form

where is an integer and
are constants with
.
-
G.
G. Gundersen and E. M. Steinbart refined Theorem A and obtained the exact forms of subnormal solutions of (1.1) as follows.
Theorem 1 B (see [6]).
In addition to the statement of Theorem A, the following statements hold with regard to the subnormal solutions of (1.1).
(i)If and
then any subnormal solution
of (1.1) must have the form

where is an integer and
are constants with
(ii)If and
, then any subnormal solution
of (1.1) must be a constant.
(iii)If , then the only subnormal solution
of (1.1) is
.
Whether the conclusions of Theorem A and Theorem B can be generalized or not, Gundersen and Steinbart considered the second-order nonhomogeneous linear differential equations

where , and
are polynomials in
such that
are not both constants. They found the exact forms of all subnormal solutions of (1.5), that is, what is mentioned in [6, Theorem ?2.2, Theorem ?2.3 and Theorem ?2.4].
In [6], they also have raised the following problem, that is, what about the forms of the subnormal solutions of the equation

where , and
are polynomials in
such that
,
,
, and
are not all constants?
In [7], we have obtained the exact forms of all subnormal solutions of homogeneous equation

where , and
are polynomials in
and are not all constants.
In this paper, we obtain the forms of subnormal solutions of nonhomogeneous linear differential equation (1.6) when . We have the following theorem.
Theorem 1.1.
Suppose that is a subnormal solution of (1.6), where
,
, and
are polynomials in
such that
and
are not all constants.
(i)If and
, then
must have the form

where is a constant,
and
are polynomials in
.
(ii)If and
, then
must have the form

where is a constant,
and
are constants that may or may not be equal to zero,
may be equal to zero or may be a polynomial in
,
, and
are polynomials in
with
.
2. Lemmas for the Proof
In order to prove Theorem 1.1, we need some lemmas.
Lemma 2.1 (see [7]).
Suppose that is a subnormal solution of (1.7), where
,
,
and
are polynomials in
and are not all constants.
(i)If and
then any subnormal solution
must be a constant.
(ii)If and
then
must have the form

where is a polynomial in
with
.
Lemma 2.2 (see [10]).
Let be a transcendental meromorphic function, let
be a given real constant, and let
. Then there exists a constant
such that the following two statements hold (where
).
(i)There exists a set that has linear measure zero such that if
, then there is a constant
such that for all
satisfying
and
one has

(ii)There exists a set that has finite logarithmic measure such that (2.2) holds for all
satisfying
.
Lemma 2.3 (see [6]).
Let with
as
and let
Let

and set

Let be analytic on the set
. Suppose that
is unbounded on the set
. Then there exists an infinite sequence of points
with
as
such that

Lemma 2.4 (see [8]).
Consider the nth- order differential equation of the form

where are polynomials in
and
with
. Suppose that
is an entire and subnormal solution of (2.6) and that
can be expressed as
, where
is a constant and
is analytic on
. Then
has the form

where is a constant and
and
are polynomials in
.
As an application of Lemma 2.4, one has the following lemma.
Lemma 2.5.
Suppose that is an entire subnormal solution of (2.6), where
are polynomials in
and
with
, and that
and
are linearly dependent. Then
has the form

where is a constant and
and
are polynomials in
.
Proof.
Since is entire and is linearly dependent with
,
can be written as
(see [11, page 382]), where
is a constant and
is analytic on
. Then we have the representation from Lemma 2.4.
Lemma 2.6.
Suppose that is a solution of (1.6), where
,
,
,
,
, and
are polynomials in
such that
,
,
and
are not all constants. If

then there exists a polynomial such that

where is a solution of

where and
are polynomials in
with
Proof.
Let and set

where is the constant such that

It follows from (1.6) and (2.12) that

where

So and
are polynomials in
and
, respectively, and
by (2.13), but
and
have the exact representations that depend on the relations of
, and
. If
, then (2.14) is of the form (2.11), and (2.12) gives (2.10). If
, then we repeat the above process finite times until we obtain (2.10) and (2.11). This completes the proof of Lemma 2.6.
3. Proof of Theorem
In this section, we will prove Theorem 1.1.
Proof.
-
(i)
Suppose that
is a subnormal solution of (1.6) with
and
. If
is a polynomial solution of (1.6), then
must be a constant, which is of the form (1.8). Thus we suppose that
is transcendental. It follows from Lemma 2.2(i) that there exists a set
that has linear measure zero such that if
, then there is a constant
such that for all
satisfying
and
, we have
(3.1)
where is a constant and
. It also follows from Lemma 2.2(ii) that there exists a set
that has finite logarithmic measure such that (3.1) holds for all
satisfying
.
Now let be an infinite sequence satisfying
such that
for all
and
as
Let
be a small constant such that
and
. Set

and set

From above, we have that (3.1) holds on the set
We now assert that is bounded on the set
. On the contrary, it follows from Lemma 2.3 that there exists a sequence of points
with
as
such that


By (1.6), we have for all ,

It follows from (3.4)–(3.6) and that (3.6) yields
as
on the set
This is a contradiction.
By the maximum modulus principle, is bounded in the angular domain

However, we know

where the integral of is defined on the simple contour
, extending from a point
to a point
in the complex domain.
So we obtain

as in the angular domain
.
Thus , from the Cauchy integral formula, we obtain

as in the angular domain
. By (1.6), (3.8), and (3.9), we have for some constant

as in the angular domain
. Together with (3.8) and (3.11),
is bounded in the angular domain
.
If , it follows from Lemma 2.5 that
must have the form (1.8).
If , since
is a subnormal solution of (1.6), so is
. Thus,

will be a subnormal solution of (1.7). Since we suppose that , we will discuss the following two cases.
Case 1.
If we have, by Lemma 2.1(i),

where is a constant. Hence
, that is,

From this, can be written as
(see [11, page 382]), where
is a constant and
is analytic on
. Thus,
can be written as
, where
is a constant and
is analytic on
. It follows from Lemma 2.4 that

where is a constant,
and
are polynomials in
. Thus,
has the form of (1.8).
Case 2.
If we obtain from Lemma 2.1(ii) that

where is a polynomial in
with
.
However, we can assert that in (3.16). Otherwise, there exists
such that

By (3.16), we have

Thus from (3.16) and (3.18), we have

By repeating this process finite times, we obtain that for any integer ,

We have, by (3.17) and (3.20),

as This is a contradiction to the fact that
is bounded in the angular domain
. This shows that
is not possible when
under the hypotheses. This completes the proof of part (i).
-
(ii)
We firstly suppose that
. Since
is a subnormal solution of (1.6), so is
. Set
(3.22)
Then is a subnormal solution of (1.7). Now if
, this shows that
and
has the form of (1.9) by Lemma 2.5. Thus, we suppose that
in the following.
Now, assume that .
If it follows from the proof of Case 1 of Theorem 1.1(i) that
has the form of (1.9).
If we obtain from Lemma 2.1(ii) that

where is a polynomial in
with
.
Set

where is an integer and
are constants with
Let and set

where
Now, we will discuss the following two cases.
Case A.
We consider in (3.24). Let
be a constant defined by

and set

Since is a subnormal solution of (1.7), it follows from (3.27) that
satisfies

We obtain from (3.23)–(3.28) that

where and
are polynomials in
with
Set

It follows from (1.6), (3.25), (3.29) and (3.30) that
Set

So , and
satisfies

We have by (3.27) that is a subnormal solution of (1.7),
is a subnormal solution of (3.29). Moreover,
is also a subnormal solution of (3.32) by (3.30) and
is a subnormal solution of (1.6). Thus, we deduce from Theorem 1.1(i) and (3.32) with
that
has the form

where is a constant,
and
are polynomials in
. Hence (3.23), (3.24), (3.27), (3.30), and (3.33) yield

where and
are constants,
, and
are polynomials in
with
. This is the form of (1.9).
Case B.
We consider in (3.24). Let
be a constant defined by

where is a number such that
is the first coefficient
in (3.24) which is not equal to zero. Set

Similar to the proof of Case A of Theorem 1.1(ii), we have

where and
are constants,
and,
are polynomials in
with
. Set
. Then
is a polynomial in
by the hypotheses of
in (3.36). This is the form of (1.9). We have proved Theorem 1.1(ii) when
Now we suppose that . By Lemma 2.6, there exists a polynomial
in
, satisfies (2.10) and (2.11).
Since and since we have proved Theorem 1.1 holds in the cases when
holds, we can apply this result to (2.11).
If , it follows from Theorem 1.1(i) that

where is a constant,
and
are polynomials in
. By (2.10) and (3.38), we obtain that

where is a constant,
and
are polynomials in
. This is a form of (1.9).
If , it follows from the proof of Theorem 1.1(ii) when
that

where and
are polynomials in
with
,
and
are constants that may or may not be equal to zero. By (2.10) and (3.40), we obtain that
has the form of (1.9). Theorem 1.1(ii) is completed.
Now, we give some examples to show that Theorem 1.1 is correct.
Example 3.1.
Let , then
satisfies

This is an example of Theorem 1.1(i).
Example 3.2.
Let , then
satisfies

This is an example of Theorem 1.1(ii) with and
.
Example 3.3.
Let , then
satisfies

This is an example of Theorem 1.1 (ii) with and
.
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Acknowledgements
The authors are very grateful to the referee for his (her) many valuable comments and suggestions which greatly improved the presentation of this paper. The project was supposed by the National Natural Science Foundation of China (no. 10871076), and also partly supposed by the School of Mathematical Sciences Foundation of SCNU, China.
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Huang, ZB., Chen, ZX. & Li, Q. Subnormal Solutions of Second-Order Nonhomogeneous Linear Differential Equations with Periodic Coefficients. J Inequal Appl 2009, 416273 (2009). https://doi.org/10.1155/2009/416273
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DOI: https://doi.org/10.1155/2009/416273
Keywords
- Entire Function
- Linear Differential Equation
- Exact Form
- Order Differential Equation
- Infinite Sequence