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Table 2 Numerical results of Example 2

From: Some results on the filter method for nonlinear complementary problems

  n = 8 n = 32 n = 100 n = 400 n = 500 n = 1000
NIT/NF 2/2 5/5 2/2 2/2 3/3 3/3
Gap 3.4578e-010 9.8173e-010 2.2257e-009 0.00028711 6.5102e-006 0.0035349
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