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Table 2 Numerical results of Example 2

From: Some results on the filter method for nonlinear complementary problems

 

n = 8

n = 32

n = 100

n = 400

n = 500

n = 1000

NIT/NF

2/2

5/5

2/2

2/2

3/3

3/3

Gap

3.4578e-010

9.8173e-010

2.2257e-009

0.00028711

6.5102e-006

0.0035349