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Table 3 The link cost function \(\pmb{t_{a}(f)}\) for Example 5.2

From: A new parallel splitting augmented Lagrangian-based method for a Stackelberg game

\(t_{1}(f)=5\cdot10^{-6}f^{4}_{1}+0.5f_{1}+0.2f_{2}+50\)

\(t_{2}(f)=3\cdot10^{-6}f_{2}^{4}+0.4f_{2}+0.4f_{1}+20\)

\(t_{3}(f)=5\cdot10^{-6}f^{4}_{3}+0.3f_{3}+0.1f_{4}+35\)

\(t_{4}(f)=3\cdot10^{-6}f_{4}^{4}+0.6f_{4}+0.3f_{5}+40\)

\(t_{5}(f)=6\cdot10^{-6}f^{4}_{5}+0.6f_{5}+0.4f_{6}+60\)

\(t_{6}(f)=0.7f_{6}+0.3f_{7}+50\)

\(t_{7}(f)=8\cdot10^{-6}f^{4}_{7}+0.8f_{7}+0.2f_{8}+40\)

\(t_{8}(f)=4\cdot10^{-6}f_{8}^{4}+0.5f_{8}+0.2f_{9}+65\)

\(t_{9}(f)=10^{-6}f^{4}_{9}+0.6f_{9}+0.2f_{10}+70\)

\(t_{10}(f)=0.4f_{10}+0.1f_{12}+80\)

\(t_{11}(f)=7\cdot10^{-6}f^{4}_{11}+0.7f_{11}+0.4f_{12}+65\)

\(t_{12}(f)=0.8f_{12}+0.2f_{13}+70\)

\(t_{13}(f)=10^{-6}f^{4}_{13}+0.7f_{13}+0.3f_{18}+60\)

\(t_{14}(f)=0.8f_{14}+0.3f_{15}+50\)

\(t_{15}(f)=3\cdot10^{-6}f^{4}_{15}+0.9f_{15}+0.2f_{14}+20\)

\(t_{16}(f)=0.8f_{16}+0.5f_{12}+30\)

\(t_{17}(f)=3\cdot10^{-6}f^{4}_{17}+0.7f_{17}+0.2f_{15}+45\)

\(t_{18}(f)=0.5f_{18}+0.1f_{16}+30\)

\(t_{19}(f)=0.8f_{19}+0.3f_{17}+60\)

\(t_{20}(f)=3\cdot 10^{-6}f_{20}^{4}+0.6f_{20}+0.1f_{21}+30\)

\(t_{21}(f)=4\cdot10^{-6}f^{4}_{21}+0.4f_{21}+0.1f_{22}+40\)

\(t_{22}(f)=2\cdot10^{-6}f_{22}^{4}+0.6f_{22}+0.1f_{23}+50\)

\(t_{23}(f)=3\cdot10^{-6}f^{4}_{23}+0.9f_{23}+0.2f_{24}+35\)

\(t_{24}(f)=2\cdot10^{-6}f_{24}^{4}+0.8f_{24}+0.1f_{25}+40\)

\(t_{25}(f)=3\cdot10^{-6}f^{4}_{25}+0.9f_{25}+0.3f_{26}+45\)

\(t_{26}(f)=6\cdot10^{-6}f_{26}^{4}+0.7f_{26}+0.8f_{27}+30\)

\(t_{27}(f)=3\cdot10^{-6}f^{4}_{27}+0.8f_{27}+0.3f_{28}+50\)

\(t_{28}(f)=3\cdot10^{-6}f_{28}^{4}+0.7f_{28}+65\)

\(t_{29}(f)=3\cdot10^{-6}f^{4}_{29}+0.3f_{29}+0.1f_{30}+45\)

\(t_{30}(f)=4\cdot10^{-6}f_{30}^{4}+0.7f_{30}+0.2f_{31}+60\)

\(t_{31}(f)=3\cdot10^{-6}f^{4}_{31}+0.8f_{31}+0.1f_{32}+75\)

\(t_{32}(f)=6\cdot10^{-6}f_{32}^{4}+0.8f_{32}+0.3f_{33}+65\)

\(t_{33}(f)=4\cdot10^{-6}f^{4}_{33}+0.9f_{33}+0.2f_{31}+75\)

\(t_{34}(f)=6\cdot10^{-6}f_{34}^{4}+0.7f_{34}+0.3f_{30}+55\)

\(t_{35}(f)=3\cdot10^{-6}f^{4}_{35}+0.8f_{35}+0.3f_{32}+60\)

\(t_{36}(f)=2\cdot10^{-6}f_{36}^{4}+0.8f_{36}+0.4f_{31}+75\)

\(t_{37}(f)=6\cdot10^{-6}f^{4}_{37}+0.5f_{37}+0.1f_{36}+35\)

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