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Table 6 The CBSN numerical results for Example 4.2 with initial \(\pmb{z_{(1)}^{0}}\)

From: A generalized Newton method of high-order convergence for solving the large-scale linear complementarity problem

  

The performance of numerical results

The solution pairs \(\boldsymbol {(u^{*},w^{*})}\)

n = 3

It

4

u∗ = (3,1.5,1)

CPU

0.0155

 

RES

0

w∗ = (0,0,0)

n = 5

It

4

u∗ = (5,2.5,1.6667,1.25,1)

CPU

0.0161

 

RES

0

w∗ = 1.0e − 015∗(0.4441,0,0,0,0)

n = 8

It

4

u∗ = (8,4,2.6667,2,1.6,1.3333,1.1429,1)

CPU

0.0163

 

RES

2.2204e − 016

\(\begin{array}{lcl} w*&=&1.0e\!-\!011*(-0.1110,0.2220,0,0,\\ &&{}0.2220,0,0,0) \end{array}\)

n = 10

It

4

\(\begin{array}{lcl} u*&=&(10,5,3.3333,2.5,2,1.6667,\\ &&{}1.4286,1.25,1.1111,1) \end{array}\)

CPU

0.0147

 

RES

8.8818e − 016

\(\begin{array}{lcl} w*&=&1.0e\!-\!014*(-0.1221,0.0444,-0.0111,\\ &&{}0.0222,0,-0.0111,0.0222,0,0,0) \end{array}\)