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Table 3 Numerical results for Example 4.1

From: A generalized Newton method of high-order convergence for solving the large-scale linear complementarity problem

Initials

 

\(\boldsymbol {z^{0}_{(1)}}\)

\(\boldsymbol {z^{0}_{(1)}}\)

\(\boldsymbol {z^{0}_{(2)}}\)

\(\boldsymbol {z^{0}_{(2)}}\)

Methods

 

GNIM

CBSN

GNIM

CBSN

n = 50

It

2

3

3

4

CPU

0.0084

0.0250

0.0119

0.0447

RES

5.7787e − 016

1.7554e − 016

5.3787e − 016

1.8619e − 016

n = 100

It

2

3

3

4

CPU

0.0135

0.0230

0.0142

0.0364

RES

6.1815e − 016

2.1678e − 016

5.6610e − 016

2.7616e − 016

n = 300

It

2

3

3

4

CPU

0.0376

0.0547

0.0562

0.0905

RES

6.2315e − 016

2.2648e − 016

5.7610e − 016

2.9616e − 016