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Table 3 The link traversing cost functions \(\pmb{t_{a}(f)}\) in the example

From: LQP method with a new optimal step size rule for nonlinear complementarity problems

\(t_{1}(f)=5\cdot10^{-5}f_{1}^{4}+5f_{1}+2f_{2}+500\)

\(t_{20}(f)=3\cdot 10^{-5}f_{20}^{4}+6f_{20}+f_{21}+300\)

\(t_{2}(f)=3\cdot10^{-5}f_{2}^{4}+4f_{2}+4f_{1}+200\)

\(t_{21}(f)=4\cdot 10^{-5}f_{21}^{4}+4f_{21}+f_{22}+400\)

\(t_{3}(f)=5\cdot10^{-5}f_{3}^{4}+3f_{3}+f_{4}+350\)

\(t_{22}(f)=2\cdot 10^{-5}f_{22}^{4}+6f_{22}+f_{23}+500\)

\(t_{4}(f)=3\cdot10^{-5}f_{4}^{4}+6f_{4}+3f_{5}+400\)

\(t_{23}(f)=3\cdot 10^{-5}f_{23}^{4}+9f_{23}+2f_{24}+350\)

\(t_{5}(f)=6\cdot10^{-5}f_{5}^{4}+6f_{5}+4f_{6}+600\)

\(t_{24}(f)=2\cdot 10^{-5}f_{24}^{4}+8f_{24}+f_{25}+400\)

\(t_{6}(f)=7f_{6}+3f_{7}+500\)

\(t_{25}(f)=3\cdot 10^{-5}f_{25}^{4}+9f_{25}+3f_{26}+450\)

\(t_{7}(f)=8\cdot10^{-5}f_{7}^{4}+8f_{7}+2f_{8}+400\)

\(t_{26}(f)=6\cdot 10^{-5}f_{26}^{4}+7f_{26}+8f_{27}+300\)

\(t_{8}(f)=4\cdot10^{-5}f_{8}^{4}+5f_{8}+2f_{9}+650\)

\(t_{27}(f)=3\cdot 10^{-5}f_{27}^{4}+8f_{27}+3f_{28}+500\)

\(t_{9}(f)=10^{-5}f_{9}^{4}+6f_{9}+2f_{1}0+700\)

\(t_{28}(f)=3\cdot 10^{-5}f_{28}^{4}+7f_{28}+650\)

\(t_{10}(f)=4f_{10}+f_{12}+800\)

\(t_{29}(f)=3\cdot 10^{-5}f_{29}^{4}+3f_{29}+f_{30}+450\)

\(t_{11}(f)=7\cdot10^{-5}f_{11}^{4}+7f_{11}+4f_{12}+650\)

\(t_{30}(f)=4\cdot 10^{-5}f_{30}^{4}+7f_{30}+2f_{31}+600\)

\(t_{12}(f)=8f_{12}+2f_{13}+700\)

\(t_{31}(f)=3\cdot 10^{-5}f_{31}^{4}+8f_{31}+f_{32}+750\)

\(t_{13}(f)=10^{-5}f_{13}^{4}+7f_{13}+3f_{18}+600\)

\(t_{32}(f)=6\cdot 10^{-5}f_{32}^{4}+8f_{32}+3f_{33}+650\)

\(t_{14}(f)=8f_{14}+3f_{15}+500\)

\(t_{33}(f)=4\cdot 10^{-5}f_{33}^{4}+9f_{33}+2f_{31}+750\)

\(t_{15}(f)=3\cdot10^{-5}f_{15}^{4}+9f_{15}+2f_{14}+200\)

\(t_{34}(f)=6\cdot 10^{-5}f_{34}^{4}+7f_{34}+3f_{30}+550\)

\(t_{16}(f)=8f_{16}+5f_{12}+300\)

\(t_{35}(f)=3\cdot 10^{-5}f_{35}^{4}+8f_{35}+3f_{32}+600\)

\(t_{17}(f)=3\cdot10^{-5}f_{17}^{4}+7f_{17}+2f_{15}+450\)

\(t_{36}(f)=2\cdot 10^{-5}f_{36}^{4}+8f_{36}+4f_{31}+750\)

\(t_{18}(f)=5f_{18}+f_{16}+300\)

\(t_{37}(f)=6\cdot 10^{-5}f_{37}^{4}+5f_{37}+f_{36}+350\)

\(t_{19}(f)=8f_{19}+3f_{17}+600\)